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3 years ago

Suppose n(U) = 150, n(A) = 35, and n(B) = 89. (a) If n(A U B) = 90, find n(A n B).

Mathematics

1 answer:

avanturin [10]3 years ago

4 0

Answer:

first of all use formula:

n(AUB)=n(A)+n(B)-n(AnB)

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A bowl of fruit contains only strawberries and grapes. For every 2 strawberries in a bowl there are 5 grapes.

sdas [7]

Answer:

See Explanation

Step-by-step explanation:

Given

Let:

$S \to$ Strawberry

$G \to$ Grape

The given parameter can be represented as:

$S : G = 2 : 5$

Required

The question is incomplete as what is required is not stated.

Possible questions could be to determine the number of strawberries given a certain number of grapes, and vice versa

Take for instance

Calculate the number of grapes when there are 20 strawberries

We have:

$S : G = 2 : 5$

This becomes

$20 : G = 2 : 5$

Express as fraction

$\frac{20}{ G} = \frac{2 }{5}$

Make G the subject

$G = 20 * \frac{5}{2}$

$G = 10 * 5$

$G = 50$

<em>i.e. 50 grapes</em>

<em>Apply the same method given a certain number of grapes</em>

8 0

3 years ago

I need help in math :(

IgorLugansk [536]

B. 8 1/5 is the answer

7 0

3 years ago

Read 2 more answers

The sodium content of a popular sports drink is listed as 200 mg in a 32-oz bottle. Analysis of 20 bottles indicates a sample me

julia-pushkina [17]

Answer:

The sample does not contradicts the manufacturer's claim.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 200 mg

Sample mean, $\bar{x}$ = 211.5 mg

Sample size, n = 20

Alpha, α = 0.05

Sample standard deviation, s = 18.5 mg

a) First, we design the null and the alternate hypothesis for a two tailed test

$H_{0}: \mu = 200\\H_A: \mu \neq 200$

We use Two-tailed t test to perform this hypothesis.

b) Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$ Putting all the values, we have

$t_{stat} = \displaystyle\frac{211.5 - 200}{\frac{18.5}{\sqrt{20}} } = 2.7799$

c) Now,

$t_{critical} \text{ at 0.05 level of significance, 19 degree of freedom } = \pm 2.0930$

Since, the calculated t-statistic does not lie in the range of the acceptance region(-2.0930,2.0930), we reject the null hypothesis.

Thus, the sample does not contradicts the manufacturer's claim.

d) P-value = 0.011934

Since the p-value is less than the significance level, we reject the null hypothesis and accept the alternate hypothesis.

Yes, both approach the critical value and the p-value approach gave the same results.

4 0

3 years ago

Sammy's Sandwich Shop has a mean delivery time of 25 minutes with a standard deviation of 2 minutes. Determine the z-score for t

fiasKO [112]

Answer:

-1

Step-by-step explanation:

Given: Mean= 25 minutes.

Standard deviation= 2 minutes

x= 23 minutes.

Lets find the z-score for the number of sandwiches delivered in less than 23 mins.

Formula: Z-score= $\frac{x-mean}{standard\ deviation}$

Z-score= $\frac{23-25}{2}$

⇒ Z-score= $\frac{-2}{2}$

∴ Z-score will be -1

Hence, -1 is the z-score for the number of sandwiches delivered in less than 23 minutes.

6 0

3 years ago

The graph of y=f(x) is above. If f(−4)=k, what is the value of f(k)?

cupoosta [38]

Answer:

The answer is B, which is -1.5.

3 0

3 years ago