The graph of the function C(x) = −0.74x2 + 22x + 75 is shown. The function models the production cost, C, in thousands of dollar
1 answer:
If the company wants to keep its production costs under $175,000, then 5.6 ≤ x ≤ 24.13 constraint is reasonable for the model given that the function C(x) = −0.74x² + 22x + 75 ,the production cost C, in thousands of dollars for a tech company to manufacture a calculator, where x is the number of calculators produced, in thousands. This can be obtained by using the given graph of the function.
<h3>Which constraint is reasonable for the model:</h3>A constraint is a condition of an optimization problem that should be satisfied the condition.
From the we have the function,
⇒ C(x) = −0.74x² + 22x + 75
the production cost C, in thousands of dollars for a tech company to manufacture a calculator, x is the number of calculators produced, in thousands.
In the graph the dotted line is the line where C(x) is $175,000. Above this line every the value is greater than $175,000.
The points where this line, that is C(x) = y = 175, intersect the graph of the given function C(x) = −0.74x² + 22x + 75 is (5.6, 175) and (24.13, 175).
- This means that above the point (5.6, 175) the graph has the value greater than 175000 and below the point the graph has the value below 175000.
- Similarly, below the point (24.13, 175) the graph has the value greater than $175,000 and above the point the graph has the value below $175,000.
Therefore, x ≥ 5.6 and x ≤ 24.13
⇒ 5.6 ≤ x ≤ 24.13
Hence if the company wants to keep its production costs under $175,000, then 5.6 ≤ x ≤ 24.13 constraint is reasonable for the model given that the function C(x) = −0.74x² + 22x + 75 ,the production cost C, in thousands of dollars for a tech company to manufacture a calculator, where x is the number of calculators produced, in thousands.
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If we follow this formula, the numerator would be the probability of (A AND B) which in this case is "48% of the class passed BOTH exams." The denominator in the formula would be that "60% of the class passed ONLY THE SECOND exam."
Therefore, P(A and B) = 0.48, which is 48% expressed as a decimal and P(B)= 0.60, which is 60% expressed as a decimal. Then, you can figure out the answer by dividing.