We have that
csc ∅=13/12
sec ∅=-13/5
cot ∅=-5/12
we know that
csc ∅=1/sin ∅
sin ∅=1/ csc ∅------> sin ∅=12/13
sec ∅=-13/5
sec ∅=1/cos ∅
cos ∅=1/sec ∅------> cos ∅=-5/13
sin ∅ is positive and cos ∅ is negative
so
∅ belong to the II quadrant
therefore
<span>the coordinates of point (x,y) on the terminal ray of angle theta are
</span>x=-5
y=12
the answer ispoint (-5,12)
see the attached figure
Answer:
I don't know if I'm right at all
x 1/2 2
5 × x2 ^
Answer:
18.18%
Step-by-step explanation:
55-45=10
10/55=0.18
Step-by-step explanation:
Given F(x) is 5 10 8 5 7 14 where x is - 1 0 1 2 3 9,
the value of F(2) is 202,478
Ok so given the point (r, theta)
The corresponding Cartesian point is (r*sin(theta), r* cos(theta)) you can think about this by analyzing the points on a unit circle which is a graph of a polar circle with radius 1 and angle theta