Question

What is p(t)=-log_10(t)^.5 in exponential form

Answer 1

Answer:

$10^{-p\left(t\right)}=t^{\left(0.5\right)}$

Step-by-step explanation:

Given equation is $p\left(t\right)=-\log_{10}t^\left(0.5\right)$

Now question says to write that in exponential form.

So we can use the following conversion formula:

$\log_ca=b\ \Rightarrow c^b=a$

$p\left(t\right)=-\log_{10}t^\left(0.5\right)$

$-p\left(t\right)=\log_{10}t^\left(0.5\right)$

$\log_{10}t^\left(0.5\right)=-p\left(t\right)$

Apply conversion formula

$p\left(t\right)=-\log_{10}t^\left(0.5\right)\ \Rightarrow 10^{-p\left(t\right)}=t^{\left(0.5\right)}$

$10^{-p\left(t\right)}=t^{\left(0.5\right)}$