Random sample of n=1300 registered voters and found that 670 would vote for the republican candidate in a state senate race. let
p represent the proportion of registered voters who would vote for the republican candidate. consider testingh0:p=.50 ha:p>.50
1 answer:
We need to test the hypotheses:
The confidence interval for proportion is
.
Here
The z value to be used is 1.96.
The 95% CI is
.
Since 0.5 lies in the interval (0.488,0.543), we cannot reject the null hypothesis with 95% confidence.
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The total weight of the other five items are 10.444 kg
<em>(round as you wish)</em>
Umm I would say that you do 0.5*0.5
so a 25% chance? Tell me if you think this is right or not, because if it's wrong I can try to help you again
Hope this helps :)
D because I answered it at school and it was correct
34 = q + n
6.1 = .25q + .05n
-1.7 = -.05q - .05n
6.1 = .25q + .05n
4.4 = .2q
q = 22
22 of the coins are quarters.
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