<span>2≤x≤8</span>
<span>−4≤<span>f′</span>(x)≤5</span>
f is continuous in differentable on [2,8] so we know there is c btw 2 and 8 such that
<span><span>f′</span>(c)=<span><span>f(8)−f(2)</span><span>/8−2</span></span></span>
And we know
<span>−4≤<span>f′</span>(c)≤5</span>
=> we have
<span>−4≤ <span><span>f(8)−f(2)</span><span>/8−2</span></span> ≤<span>5</span></span>
Answer:
it D
Step-by-step explanation:
Trust me
djrjnfnzenngfzm
The type of model that best fits the given situation is; A linear equation Model
<h3>What is the model of the equation?</h3>
Right inside the local reservoir we will have an initial amount of water A.
Now, for every hour that passes by, the amount of water in the reservoir decreases by 500 gals.
Thus, after t hours, the amount of water in the reservoir is expressed as:
W = A - 500gal * t
This is clearly a linear equation model and so we can conclude that the model that fits best in the given situation is a linear model.
The domain of this model is restricted because we can't have a negative amount of water in the reservoir, and as such the maximum value of t accepted is: W = 0 = A - 500gal*t
t = A/500 hours
Therefore, the domain of this linear relation is: t ∈ {0h, A/500 }
Read more about Equation model at; brainly.com/question/25896797
#SPJ1
Because both lines are parallel, if you add the 5x+5 to the 115 those would equal 180 degrees
so you have 5x+5 + 115 = 180
combine like terms:
5x + 120 = 180
subtract 120 from both sides
5x = 60
x = 60/5
x = 12
Answer:
5
Step-by-step explanation:
like my answer please...
