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asambeis [7]
3 years ago
10

Please help me out with this!!

Mathematics
1 answer:
galina1969 [7]3 years ago
7 0

Answer:

see explanation

Step-by-step explanation:

Given

x + \frac{1}{2} ≤ - 3 or x - 3 > - 2

Solve the left and right inequalities separately, that is

x + \frac{1}{2} ≤ - 3 ( isolate x by subtracting \frac{1}{2} from both sides )

x ≤ - 3 - \frac{1}{2}, that is

x ≤ - \frac{6}{2} - \frac{1}{2}, thus

x ≤ - \frac{7}{2}

OR

x - 3 > - 2 ( isolate x by adding 3 to both sides )

x > 1

Solution is

x ≤ - \frac{7}{2} or x > 1

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<h3>Solution:</h3>

given \:  \: a=2,b=-3,c=1,d=-2 \\ then \:  \: d + 2c - (3a - 2b) \\  = ( - 2) + 2(1) - (3 \times 2 - 2 \times  -3) \\  =  - 2 + 2 - (6 + 6) \\  = 0 - 12 \\  =  - 12

<h3>Answer:</h3>

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<h3>Hope it helps..</h3>

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