Question

Please help me out with this!!

Answer 1

Answer:

see explanation

Step-by-step explanation:

Given

x + $\frac{1}{2}$ ≤ - 3 or x - 3 > - 2

Solve the left and right inequalities separately, that is

x + $\frac{1}{2}$ ≤ - 3 ( isolate x by subtracting $\frac{1}{2}$ from both sides )

x ≤ - 3 - $\frac{1}{2}$, that is

x ≤ - $\frac{6}{2}$ - $\frac{1}{2}$, thus

x ≤ - $\frac{7}{2}$

OR

x - 3 > - 2 ( isolate x by adding 3 to both sides )

x > 1

Solution is

x ≤ - $\frac{7}{2}$ or x > 1