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Advocard [28]
1 year ago
8

PLEASE HELP!!! Which point is tangent to the circle? A D M Q

Mathematics
1 answer:
lisov135 [29]1 year ago
6 0

Answer:

M is target to the circle

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A number is 2 tens more than 993. What is the number?
Effectus [21]

Answer:

1013

Step-by-step explanation:

993 + 10 + 10.

4 0
2 years ago
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Sry about the scribbles I was trying but I need help ASAP so try to answer it as fast as possible
QveST [7]

Answer:

The answer for A is 1500 and B is 150

Step-by-step explanation:

All you need to do is first make 25% into 25 over 100 or 25/100 then you divide which will give you 0.25 next you're gonna have to divide 375 by 0.25 which is 1,500. Then for B it do it again 60% to 60/100 next turn it into a decimal which is 0.60 or 0.6 then multiply 375 by 0.6 which is 225 then subtract 375 by 225 then you got the final answer:150. I hope I helped you

5 0
3 years ago
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(4 + 32)(15 – 23)<br> can someone help me out with the answer? :,)
hoa [83]

Answer:

-288

Step-by-step explanation: I took the following steps to find the answer:

(4 + 32)(15 – 23)

\             /

 (36)(15 – 23)

           \          /

 (36) (- 8)

   \        /

    -288

4 0
2 years ago
Need help please!! 15 points
marusya05 [52]

Answer:

The average of -2.5, 5.2, 1.7, and -0.8 is <u>0.9</u>

Step-by-step explanation:

You are taking the mean of all the values

So you would add -2.5, 5.2, 1.7, and -0.8 all together

This gives you 3.6

Then you would divide by the number of numbers per se,

Which would give you the answer: 0.9

8 0
3 years ago
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2.<br> Which of the functions below is an inverse of the quadratic function f(x) = x2 - 3 ?
mezya [45]

Answer:

the inverse of the quadratic function f(x) = x^2 - 3  is \mathbf{f^{-1}(x)=\pm \sqrt{x+3}}

Step-by-step explanation:

We need to find inverse of the quadratic function f(x) = x^2 - 3

Let

y=x^2-3

Replace x and y

x=y^2-3

Now, we will solve for y

Adding 3 on both sides

x+3=y^2-3+3

x+3=y^2

Taking square root on both sides

\sqrt{y^2}=\sqrt{x+3}\\y=\pm \sqrt{x+3}

Now replace y with f^{-1}(x)

f^{-1}(x)=\pm \sqrt{x+3}

So, the inverse of the quadratic function f(x) = x^2 - 3  is \mathbf{f^{-1}(x)=\pm \sqrt{x+3}}

3 0
2 years ago
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