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2 years ago

Y= 3x+7 y = -2x-3 What would be the x and y for that solution

Mathematics

1 answer:

alexandr402 [8]2 years ago

6 0

Answer:

So if we are solving for x and y. First we need to subtract both equations. We take each equation and put in parenthesis and subtract.

y-y = (3x+7)-(-2x-3) =

0 = 3x+7+2x+3

0 = 5x+10

-10 = 5x

-2 = x.

Now we need to solve for y.

Plug it in for the first equation. -2*3+7 = -6+7 = 1

Test if we are correct and try in the second equation.

-2*-2-3 = 4-3 = 1

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2 years ago

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2 years ago

Which of the following is the product of the rational expressions shown below? 7x/x-4•x/x+7

Gre4nikov [31]

<h2>The product of the rational expressions $\dfrac{7x}{x-4}.\dfrac{x}{x+7} = \dfrac{7x^2}{x^2+3x-28}$ .</h2>

Step-by-step explanation:

We have,

$\dfrac{7x}{x-4}.\dfrac{x}{x+7}$

To find, the product of the rational expressions $\dfrac{7x}{x-4}.\dfrac{x}{x+7}$ = ?

∴ $\dfrac{7x}{x-4}.\dfrac{x}{x+7}$

= $\dfrac{7x.x}{(x-4)(x+7)}$

= $\dfrac{7x^2}{(x(x+7)-4(x+7)}$

= $\dfrac{7x^2}{x^2+7x-4x-28}$

= $\dfrac{7x^2}{x^2+3x-28}$

Thus, the product of the rational expressions $\dfrac{7x}{x-4}.\dfrac{x}{x+7} = \dfrac{7x^2}{x^2+3x-28}$ .

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2 years ago

If the ratio of the sides of two similar prisms is 3:5 and the volume of the first prism is 54, what is the volume of the second

Yuri [45]

$\bf \qquad \qquad \textit{ratio relations}
\\\\
\begin{array}{ccccllll}
&Sides&Area&Volume\\
&-----&-----&-----\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3}
\end{array} \\\\
-----------------------------\\\\$

$\bf \cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\
-------------------------------\\\\
\cfrac{smaller}{larger}\qquad \cfrac{s^3}{s^3}=\cfrac{\textit{volume of smaller}}{\textit{volume of larger}}\implies \cfrac{3^3}{5^3}=\cfrac{54}{v}
\\\\\\
v=\cfrac{5^3\cdot 54}{3^3}$

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2 years ago

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Yakvenalex [24]

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2 years ago