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3 years ago

Y= 3x+7 y = -2x-3 What would be the x and y for that solution

Mathematics

1 answer:

alexandr402 [8]3 years ago

6 0

Answer:

So if we are solving for x and y. First we need to subtract both equations. We take each equation and put in parenthesis and subtract.

y-y = (3x+7)-(-2x-3) =

0 = 3x+7+2x+3

0 = 5x+10

-10 = 5x

-2 = x.

Now we need to solve for y.

Plug it in for the first equation. -2*3+7 = -6+7 = 1

Test if we are correct and try in the second equation.

-2*-2-3 = 4-3 = 1

x = -2

y = 1

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Step-by-step explanation:

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Answer:

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Given the function:

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3 years ago

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Step-by-step explanation:

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3 years ago

Help with trigonometry

Oksanka [162]

Answer:

○B. $\frac{\sqrt{6}}{2}$

Step-by-step explanation:

Trigonometric Identities

$\frac{y}{r} = sin\:θ$

$\frac{x}{r} = cos\:θ$

$\frac{y}{x} = tan\:θ$

$\frac{r}{x} = sec\:θ$

$\frac{r}{y} = csc\:θ$

$\frac{x}{y} = cot\:θ$

Radius Formula

${y}^{2} + {x}^{2} = {r}^{2}$

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In this case, we will not be using the radius in our ratio, according to the trigonometric identity above because we are using the tangent ratio:

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I am joyous to assist you anytime.

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