1. The remaing area of the yard will be found as follows:
Area of the yard
A1=length*width=10x*15x=150x^2 yd^2
area of the fountain
A2=πr²
A2=π(4x)²
=50.266x^2
The remaining area will be:
A=150x^2-50.266x^2
A=99.735x^2 yd^2
2] Area left for bleachers, restrooms and other parts of the stadium will be as follows:
Area of the lot is:
A1=length*width
A1=8x×12x= 96x^2
Area of the field
A2=length×width
A2=3x×6x=18x^2
Hence the remaining area will be:
A1-A2
=96x^2-18x^2
=78x^2 sq. units
Answer:
for the triangle on top on side is 8 one side is 4 so if we use the theorem
64+16=80
a=9
so
Side a = 19.8242
Side b = 17.66349
Side c = 9
Angle ∠A = 90° = 1.5708 rad = π/2
Angle ∠B = 63° = 1.09956 rad = 7/20π
Angle ∠C = 27° = 0.47124 rad = 3/20π
Area = 79.48573
Perimeter p = 46.4877
Semiperimeter s = 23.24385
Answer:
The value of 
is 
.
Step-by-step explanation:
The given equation is
We need to find the value of .
Differentiate with respect to t.
![[\because \frac{d}{dx}x^n=nx^{n-1},\frac{d}{dx}C=0]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Cfrac%7Bd%7D%7Bdx%7Dx%5En%3Dnx%5E%7Bn-1%7D%2C%5Cfrac%7Bd%7D%7Bdx%7DC%3D0%5D)
It is given that y=2 and dy/dt=1, substitute these values in the above equation.
Divide both sides by 4x³.
Therefore the value of is .
Answer:
$9.25
Step-by-step explanation:
$18.50 divided by 2 equals $9.25.
ANSWER: Acts
EXPLANATION: The major divisions in a play script are called Act. An Act is a group of two or more scenes that form a major division of a play. It is a part of the play which includes elements such as action, romance, climax and resolution. Scenes are the part of the act with change in characters.
