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Nataly [62]
3 years ago
15

Gerry has 50 sports trading cards. Of those cards one fifth of them are baseball cards, one teenth of them are football cards, a

nd the rest are basketball cards. How many more basketball cards than baseball cards does gerry have?
Mathematics
1 answer:
Pachacha [2.7K]3 years ago
8 0

Answer: Gerry has 25 more basketball cards than baseball cards.

Step-by-step explanation:

The total number of sports trading cards that Gerry has is 50.

Of those cards one fifth of them are baseball cards. It means that the number of baseball cards that he has is

1/5 × 50 = 10

one tenth of them are football cards. It means that the number of football cards that he has is

1/10 × 50 = 5

The rest are basketball cards. It means that the number of basketball cards that he has is

50 - (10 + 5) = 35 basketball cards

The difference between the number of basketball and baseball cards that he has is

35 - 10 = 25

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Answer:

4.464 ml

Step-by-step explanation:

Given that:

mean (μ) = 5 mm, standard deviation (σ) = 0.4 ml

The z score is a score in statistics used to determine by how many standard deviation the raw score is above or below the mean. If the z score is positive then the raw score is above the mean and if the z score is negative then the raw score is below the mean It is given by:

z=\frac{x-\mu}{\sigma}

From the normal distribution table, the 9th percentile (0.09) corresponds to a z score of -1.34

z=\frac{x-\mu}{\sigma}\\\\-1.34=\frac{x-5}{0.4}\\\\x-5=-0.536\\\\x=5-0.536\\\\x=4.464

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A new Community Center is being built in Oak Valley. The perimeter of the rectangular playing field is 382 yards. The length of
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Answer:

The width is 50 yards and the length is 141 yards.

Step-by-step explanation:

Let's call: L the length of the field and W the width of the field.

From the sentence, the perimeter of the rectangular playing field is 382 yards we can formulate the following equation:

2L + 2W = 382

Because the perimeter of a rectangle is the sum of two times the length with two times the width.

Then, from the sentence, the length of the field is 9 yards less than triple the width, we can formulate the following equation:

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So, replacing this last equation on the first one and solving for W, we get:

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