There are the combinations that result in a total less than 7 and at least one die showing a 3:
[3, 3] [3,2] [2,1] [1,3] [2,3]
The probability of each of these is 1/6 * 1/6 = 1/36
There is a little ambiguity here about whether or not we should count [3,3] as the problem says "and one die shows a 3." Does this mean that only one die shows a 3 or at least one die shows a 3? Assuming the latter, the total probability is the sum of the individual probabilities:
1/36 + 1/36 + 1/36 + 1/36 + 1/36 = 5/36
Therefore, the required probability is: 5/36
Hello!
The words at least means that the worker needs to work 8, 9 or 10 hours. We can add probabilities, so we will add .6 (for those working 8 hours), .15 (for those working 9 hours) and .08 (for those working 10 hours) to get a total probability of .83.
Hope this helps!
Answer:
=60 cm
Step-by-step explanation:
i took the test
Answer:
i think 9
Step-by-step explanation:
