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Oksi-84 [34.3K]
3 years ago
7

Will u please help me! I'm so confused

Mathematics
1 answer:
likoan [24]3 years ago
8 0
A- 0.4
B- ?
C- ?
D- 0.525
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The diameter of a circle is 20 centimeters. What is the radius?
Mama L [17]

Answer:

10

Step-by-step explanation:

radius is the middle point of a circle, therefore divide it in half.

8 0
3 years ago
If Diana walks forward and her angle looking to the top of the building changes to 40°, how much closer is she to the building?
elena55 [62]

The closer Diana gets to the building, the smaller the angle becomes

Diana is 17.6 feet closer to the building

<h3>How to calculate the distance from the building</h3>

To calculate the distance between her and the building, we make use of the following tangent ratio

\tan(\theta) = \frac{h}{d}

Where:

  • \theta = 40^o
  • h represents the height of the building; h = 130
  • d represents the distance from the building

So, we have:

\tan(40) = \frac{130}{d}

Make d the subject

d = \frac{130}{\tan(40)}

Evaluate tan(40)

d = \frac{130}{0.8391}

d = 154.93

Initially, Diana is at a distance of 172.53.

The difference in both distance is:

\Delta d = 172.53 - 154.93

\Delta d = 17.6

Hence, Diana is 17.6 feet closer to the building

Read more about trigonometry ratios at:

brainly.com/question/4326804

7 0
2 years ago
9y^2-6y+1=0<br> FIND Y PLEASE HELP STEP BY STEP
dlinn [17]

Answer:

y = 1/3

Step-by-step explanation:

<u>Step 1:  Factor</u>

9y^2 - 6y + 1 = 0

(3y - 1)(3y - 1) = 0

(3y - 1)^2 = 0

<u>Step 2:  Solve for y</u>

3y - 1 + 1 = 0 + 1

3y / 3 = 1 / 3

y = 1/3

Answer: y = 1/3

4 0
3 years ago
A rancher has 4 comma 700 feet of fencing available to enclose a rectangular area bordering a river. he wants to separate his co
guapka [62]
Area=length*width
let the sides perpendicular to the river be x
then  the side parallel to the river is 4,700-2x 
A(x)=x(4700-2x)
A(x)=4700x-2x^2

This a quadratic function with a=-2 and b=4700
thus
Maximum area occurs where x=-b/2a=-4700(-2*2)=1,175 ft
length=4700-2(1175)=2,350 ft
4 0
4 years ago
How<br>Solve The D. E<br><br> dy/dx=2x^5 y^3 - 4y/x<br><br>​
Pachacha [2.7K]
Dy/dx (2x⁵ y³ - 4y/x)

dy/dx (2y³ x⁵ - 4y/x)

dy/dx ( 2y³ x⁵ ) - dy/dx (4y/x)

= 2y³ 5x⁴ - (-4y × 1/x²)

=
10x⁶ y³ + 4y
-------------------
x²

3 0
3 years ago
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