All categories

3 years ago

I NEED HELP IN MATH

Mathematics

1 answer:

frutty [35]3 years ago

7 0

Its the second choice

You might be interested in

Solve the equation for all real values of x. cosxtanx - 2 cos x=-1

IceJOKER [234]

Solution to equation $cosxtanx - 2 cos^2 x=-1$ for all real values of x is $x=2k\pi + \frac{\pi}{6} , x=2k\pi + \frac{5\pi}{6}$ .

Step-by-step explanation:

Here we have , $cosxtanx - 2 cos^2 x=-1$ . Let's solve :

⇒ $cosxtanx - 2 cos^2 x=-1$

⇒ $cosx(\frac{sinx}{cosx}) - 2 cos^2 x=-1$

⇒ $sinx = 2 cos^2 x-1$

⇒ $sinx = 2 (1-sin^2x)-1$

⇒ $sinx = 1-2sin^2x$

⇒ $2sin^2x+sinx-1=0$

By quadratic formula :

⇒ $sinx = \frac{-b \pm \sqrt{b^2-4ac} }{2a}$

⇒ $sinx = \frac{-1 \pm \sqrt{1^2-4(2)(-1)} }{2(2)}$

⇒ $sinx = \frac{-1 \pm3}{4}$

⇒ $sinx = \frac{1}{2} , sinx =-1$

⇒ $sinx = sin\frac{\pi}{6} , sinx = sin\frac{3\pi}{2}$

⇒ $x=\frac{\pi}{6} , x=\frac{3\pi}{2}$

But at $x=\frac{3\pi}{2}$ we have equation undefined as $cos\frac{3\pi}{2}=0$ . Hence only solution is :

⇒ $x=\frac{\pi}{6}$

Since , $sin(\pi -x)=sinx$

⇒ $x=\pi -\frac{\pi}{6} = \frac{5\pi}{6}$

Now , General Solution is given by :

⇒ $x=2k\pi + \frac{\pi}{6} , x=2k\pi + \frac{5\pi}{6}$

Therefore , Solution to equation $cosxtanx - 2 cos^2 x=-1$ for all real values of x is $x=2k\pi + \frac{\pi}{6} , x=2k\pi + \frac{5\pi}{6}$ .

3 0

3 years ago

2. Given square CANE with diagonals

svlad2 [7]

What’s something goes up but never comes down?

6 0

3 years ago

PLEASE HELP WILL GIVE OUT BRAINLEYST MATHH PEOPLE HELP

Umnica [9.8K]

Answer its 82 i added the cm

3 0

3 years ago

Can someone explain how to do this and the answer?

inysia [295]

Step-by-step explanation:

Helo

your answer refer to the attachment

7 0

3 years ago

Which of the following graphs best represents f(x) = −2 sin(4x) + 3?

Artist 52 [7]

The graph for f(x) = sin x is a sinusoidal graph.

f(x) = 2 sin 4x
has an amplitude of 2 or the highest point is 2 and a period of
Period = 3π/4 = π/3
f(x) = 2 sin 4x + 3
the graph is shifted 3 points upward.

3 0

3 years ago