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3 years ago

11

Question 1 (1 point)

1 answer:

Natalija [7]3 years ago

5 0

Answer: OPTION B.

Step-by-step explanation:

Given the equation $48=-8(\frac{3b}{4}+2)$ you can find an equivalent equation by simplifying it.

You need to remember the multiplication of signs:

$(-)(-)=+\\(+)(+)=+\\(+)(-)=-$

Now you can apply the Distributive property:

$48=\frac{(-8)(3b)}{4}+(-8)(2)\\\\48=\frac{-24b}{4}-16$

Simplifying the equation, you get:

$48=-6b-16$

You can observe that this equivalent equation matches with the equation provided in option B.

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Pls help u need to simplify an equation but write the answer as a power

eduard

Raise

3.8

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8 0

3 years ago

What the answer to this <br><br><br> -3+u=-20

yawa3891 [41]

- 3 + u = - 20

u = - 20 + 3

u = -17

hope this helps!.

5 0

3 years ago

Read 2 more answers

Find all the solutions for the equation:

Contact [7]

$2y^2\,\mathrm dx-(x+y)^2\,\mathrm dy=0$

Divide both sides by $x^2\,\mathrm dx$ to get

$2\left(\dfrac yx\right)^2-\left(1+\dfrac yx\right)^2\dfrac{\mathrm dy}{\mathrm dx}=0$

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2\left(\frac yx\right)^2}{\left(1+\frac yx\right)^2}$

Substitute $v(x)=\dfrac{y(x)}x$ , so that $\dfrac{\mathrm dv(x)}{\mathrm dx}=\dfrac{x\frac{\mathrm dy(x)}{\mathrm dx}-y(x)}{x^2}$ . Then

$x\dfrac{\mathrm dv}{\mathrm dx}+v=\dfrac{2v^2}{(1+v)^2}$

$x\dfrac{\mathrm dv}{\mathrm dx}=\dfrac{2v^2-v(1+v)^2}{(1+v)^2}$

$x\dfrac{\mathrm dv}{\mathrm dx}=-\dfrac{v(1+v^2)}{(1+v)^2}$

The remaining ODE is separable. Separating the variables gives

$\dfrac{(1+v)^2}{v(1+v^2)}\,\mathrm dv=-\dfrac{\mathrm dx}x$

Integrate both sides. On the left, split up the integrand into partial fractions.

$\dfrac{(1+v)^2}{v(1+v^2)}=\dfrac{v^2+2v+1}{v(v^2+1)}=\dfrac av+\dfrac{bv+c}{v^2+1}$

$\implies v^2+2v+1=a(v^2+1)+(bv+c)v$

$\implies v^2+2v+1=(a+b)v^2+cv+a$

$\implies a=1,b=0,c=2$

Then

$\displaystyle\int\frac{(1+v)^2}{v(1+v^2)}\,\mathrm dv=\int\left(\frac1v+\frac2{v^2+1}\right)\,\mathrm dv=\ln|v|+2\tan^{-1}v$

On the right, we have

$\displaystyle-\int\frac{\mathrm dx}x=-\ln|x|+C$

Solving for $v(x)$ explicitly is unlikely to succeed, so we leave the solution in implicit form,

$\ln|v(x)|+2\tan^{-1}v(x)=-\ln|x|+C$

and finally solve in terms of $y(x)$ by replacing $v(x)=\dfrac{y(x)}x$ :

$\ln\left|\frac{y(x)}x\right|+2\tan^{-1}\dfrac{y(x)}x=-\ln|x|+C$

$\ln|y(x)|-\ln|x|+2\tan^{-1}\dfrac{y(x)}x=-\ln|x|+C$

$\boxed{\ln|y(x)|+2\tan^{-1}\dfrac{y(x)}x=C}$

7 0

3 years ago

This week Aaron got a promotion at work that came with a 3 % pay increase. If now his monthly salary is $ 2163 , how much was he

NNADVOKAT [17]

Answer:

12.75

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Find a area of a circumference that is 13 ft for 3.14 π

Elena-2011 [213]

Answer:

4.14x3.14=12.9996

Step-by-step explanation:

This is the closest to 13 ft via circumference

Here is a few equations a dn formulas to remind you.

Area=3.14xRxR or Pi*rr

This is Pi times the radius times the radius.

The radius is half of the circle or half of the Diameter.

Area(semi-circle)=1/2x3.14xrxr

Circumfrence=3.14xDor 3.14xdiameter

<u><em>If this answer helped pls give brainlest.</em></u>

8 0

2 years ago