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2 years ago

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Mathematics

1 answer:

maxonik [38]2 years ago

4 0

Answer:

20mm, 1mm, 20mm

Step-by-step explanation:

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Subtract the equation m-3n/6m3n - m+3n/6m^3n

Sergio039 [100]

Answer:

- n^2m(3 - m^2)/2

3 0

2 years ago

I need to know number six and thank you guys for all the help

Zigmanuir [339]

Answer:

Step-by-step explanation:

First of all, a very easy way is to count all the rectangles and then count the squares that are shaded and have balloons.

You'll get 7 squares that are shaded and have balloons and 16 rectangles in total.

So the fraction will be $\frac{7}{16}$

Another simple way is to just multiply $\frac{7}{8}$ and $\frac{1}{2}$

$\frac{7}{8}*\frac{1}{2}=\frac{7}{16}$

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3 years ago

Need to know the area of the composite figure.

MatroZZZ [7]

Answer:

52.5 cm^2

Step-by-step explanation:

The base length of the triangle on top is ...

8 cm - 1 cm - 2 cm = 5 cm

Then the area of that triangle is given by the formula ...

A = (1/2)bh = (1/2)(5 cm)(5 cm) = 12.5 cm^2

___

The area of the rectangle below that triangle is the product of its length and width:

A = (8 cm)(5 cm) = 40 cm^2

___

The total area is the sum of the areas of the rectangle and triangle, so is ...

total area = 40 cm^2 + 12.5 cm^2 = 52.5 cm^2

8 0

3 years ago

Graph DEF and its image when you translate DEF using vector

adelina 88 [10]

Answer:

The image coordinates are D'(8, 5), E'(12, 3) and F'(10,0)

Step-by-step explanation:

Given the vertices of △ DEF are D (2, 5), E (6, 3), and F (4, 0). We have to translate the triangle using the vector (6, 0)

Now, translation by vector (6, 0)

D (2, 5)=D'(2+6, 5+0)=D'(8, 5)

E (6, 3)=E'(6+6, 3+0)=E'(12, 3)

F (4, 0)=F'(4+6, 0+0)=F'(10,0)

Now, we have to label the coordinate of the triangle or to get image of triangle after translation.

Hence, The image coordinates are D'(8, 5), E'(12, 3) and F'(10,0)

Step-by-step explanation:

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3 years ago

Solve one step and two step problems

Nastasia [14]

1. First would be 9-4+7=13
2. Second one is 4+6-2=8

5 0

3 years ago

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Help ajajsjsnsnsjsjs