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sasho [114]
3 years ago
7

The temperature in the late afternoon

Mathematics
2 answers:
Fantom [35]3 years ago
6 0

Answer:

-7.5 - (8.5 + 5)

Step-by-step explanation:

We just add together the values of how much it dropped at different parts of the day, and subtract them from what we started with. The parenthesis are important cause we want to know what the total temperature drop for the day was before we subtract it to get the actual temperature we end up with.

Crazy boy [7]3 years ago
6 0

Answer:

T= - 5°C - 8.5°C = -13.5°C

Step-by-step explanation:

The initial temperature in the late afternoon was -7.5°C.

It dropped 5 degrees by early evening and then dropped 8.5 degrees by midnight.

Change in temperature (in evening) = -5°C

Change in temperature (in midnight) = -8.5°C

Here negative sign represents the decrease in the temperature.

Let T be the total change in the temperature.

So, total change in the temperature is

T = - 5°C - 8.5°C

T = 13.5°C

Therefore, the required equation is T = - 5°C - 8.5°C = 13.5°C.

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Show work and explain with formulas:
Marina86 [1]

17 Answer:  205

<u>Step-by-step explanation:</u>

\{1\dfrac{2}{3}+1\dfrac{5}{6}+2+...+8\dfrac{1}{3}\}\implies a_1=1\dfrac{2}{3},\ d=\dfrac{1}{6}\\\\\\a_n=a_1+d(n-1)\qquad solve\ for\ n\\\\8\dfrac{1}{3}=1\dfrac{2}{3}+\dfrac{1}{6}(n-1)\\\\\\\dfrac{25}{3}=\dfrac{5}{3}+\dfrac{1}{6}n-\dfrac{1}{6}\\\\\\\dfrac{50}{6}=\dfrac{10}{6}+\dfrac{1}{6}n-\dfrac{1}{6}\\\\\\\dfrac{41}{6}=\dfrac{1}{6}n\\\\\\\dfrac{41}{6}\cdot 6=n\\\\41=n

\text{Now use the sum formula:}\\\\S_n=\dfrac{a_1+a_n}{2}\cdot n\\\\\\S_{41}=\dfrac{1\dfrac{2}{3}+8\dfrac{1}{3}}{2}\cdot 41\\\\\\.\quad =\dfrac{10}{2}\cdot 41\\\\\\.\quad =5\cdot 41\\\\.\quad =\large\boxed{205}

18 Answer:  1968

<u>Step-by-step explanation:</u>

a_1=-6,\ d=2,\ n=48, \quad \text{solve for }a_{48}\\\\a_{n}=a_1+d(n-1)\\\\a_{48}=-6+2(48-1)\\\\.\quad =-6+2(47)\\\\.\quad =-6+94\\\\.\quad =88

\text{Now use the sum formula:}\\\\S_n=\dfrac{a_1+a_n}{2}\cdot n\\\\\\S_{48}=\dfrac{-6+88}{2}\cdot 48\\\\\\.\quad =\dfrac{82}{2}\cdot 48\\\\\\.\quad =41\cdot 48\\\\.\quad =\large\boxed{1968}

19 Answer:  -116

<u>Step-by-step explanation:</u>

\{3, -2, -7, ...\}\\a_1=3,\ d=-5,\ n=8, \quad \text{solve for }a_{8}\\\\a_{n}=a_1+d(n-1)\\\\a_{8}=3-5(8-1)\\\\.\quad =3-5(7)\\\\.\quad =3-35\\\\.\quad =-32\\\\\text{Now use the sum formula:}\\\\S_8=\dfrac{a_1+a_8}{2}\cdot 8\\\\\\S_{8}=\dfrac{3-32}{2}\cdot 8\\\\\\.\quad =\dfrac{-29}{2}\cdot 8\\\\\\.\quad =-29\cdot 4\\\\.\quad =\large\boxed{-116}

6 0
2 years ago
Graft the solution to the inequality on the number line. <br><br><br> m&gt;2.8
Oduvanchick [21]

Answer:

See the graph of the given inequality in the attachment as shown below:

Step-by-step explanation:

Given the inequality: m > 2.8

To graph this inequality on the number line.

Remember:

  • If the symbol is (\geq or \leq) then you fill in the dot
  • If  the symbol is (> or then you do not fill in the dot.

Since, in the given inequality the symbol is '>'

Now, sketch a number line and draw an open circle around the number 2.8.

You can see the number line as shown below in the attachment.


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3 years ago
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