Two fuel tanks with the dimensions shown have the same volume. What is the value of h?
1 answer:
(See attached picture for the diagram of both fuel tanks)
Answer:
2ft
Step-by-step Explanation:
==> Given:
Two cylindrical fuel tanks, one has a radius of 3ft, and height of 8ft, the second tank has a radius of 6ft and unknown height.
Also, volume of 1st tank = volume of 2nd tank
==> Required:
Find h = unknown height of the the 2nd tank.
=>Solution:
To find the height of the 2nd tank = h, we need to know the volume. Thus, volume of first tank = volume of 2nd tank.
Since the dimensions of the 1st tank are all given, let's find its volume.
Thus, volume of 1st tank using the formula V = πr²h (where π = 3.14, r = 3ft, h = 8ft)
V = 3.14*3²*8
= 3.14*9*8 = 226.08 ft³
Volume of first tank = volume of 2nd tank = 226.08 ft³
=> Let's find the height of the 2nd tank with same volume of 226.08ft³
Therefore, V = πr²h (V = 226.08, r = 6ft, h = ?)
226.08 = 3.14*6²*h
226.08 = 3.14*36*h
226.08 = 113.04*h
226.08/113.04 = h
2 = h
Height of the second fuel tank (h) = 2ft
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Answer: Option b.
Step-by-step explanation:
1. You have the following parent function given in the problem above:
f(x)=x³ (This is the simplest form. We need to translate it 3 units left and 2 units down)
2. If you take the parent function and make y=f(x+3), then you have:
(The function is shifted 3 units left on the x-axis).
3. Then you if you make y=f(x+3)-2, as following, you obtain:
(The function is shifted 2 units down on the y-axis).
4. Therefore, that is how you obtain the final function.
The answer is the graph shown in the option b.
Here is the graph. (I got it from desmos.com...its a good graphing site) I hope this helps love! :)
