Answer:
I suppose we want to find the side length of the square.
We know that:
The area of the square is 49cm^2
The distance between one of the vertices of the square and the middle of the square is:
BE = 4.95cm
Now let's remember some things.
For a square of side length L, the area is:
A = L^2
and the diagonal length is:
D = √(2)*L
In this case, we know that half of the diagonal is equal to:
BE = 4.95 cm
Then the diagonal is:
D = 2*BE = 2*4.95cm = 9.9cm
And for the diagonal formula, we have:
D = 9.9cm = √(2)*L
Then the side length is:
L = 9.9cm/√(2) = 7cm
And if we check the area of this square, is:
A = L^2 = (7cm)^2 = 49cm^2
So it checks.
Then we can conclude that the sidelength of the square is 7cm, which means that:
AB = 7cm
BC = 7cm
CD = 7cm
DA = 7cm
ITS IS 8x-7y-5z=15 I THINK'
Answer:
x = 9
Step-by-step explanation:
81/9=9
The Given Triangle PMO is a Right Angled Triangle with m∠M = 90°
Given m∠P = 40°
We know that : Sum of Angles in a Triangle = 180°
⇒ m∠P + m∠M + m∠O = 180°
⇒ 40° + 90° + m∠O = 180°
⇒ 130° + m∠O = 180°
⇒ m∠O = 180° - 130°
⇒ m∠O = 50°
We can notice that m∠O and m∠1 form a Linear Pair (180°)
⇒ m∠O + m∠1 = 180°
⇒ 50° + m∠1 = 180°
⇒ m∠1 = 180° - 50°
⇒ m∠1 = 130°
Last Option is the Answer
96=4P+2(8)
96=4P+16
80=4P
P=20
