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Sidana [21]
3 years ago
7

(5x - 2y)^3 Expand using Bionomial Theorum. Show steps, please.

Mathematics
1 answer:
tatyana61 [14]3 years ago
7 0

Answer:

125x³ − 150x²y + 60xy² − 8y³

Step-by-step explanation:

(5x − 2y)³

₃C₀ (5x)³ (-2y)⁰ + ₃C₁ (5x)² (-2y)¹ + ₃C₂ (5x)¹ (-2y)² + ₃C₃ (5x)⁰ (-2y)³

(1) (125x³) (1) + (3) (25x²) (-2y) + (3) (5x) (4y²) + (1) (1) (-8y³)

125x³ − 150x²y + 60xy² − 8y³

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Suppose 52% of the population has a college degree. If a random sample of size 563563 is selected, what is the probability that
amm1812

Answer:

The value is  P(| \^ p -  p| < 0.05 ) = 0.9822

Step-by-step explanation:

From the question we are told that

    The population proportion is  p =  0.52

     The sample size is  n  =  563      

Generally the population mean of the sampling distribution is mathematically  represented as

           \mu_{x} =  p =  0.52

Generally the standard deviation of the sampling distribution is mathematically  evaluated as

       \sigma  =  \sqrt{\frac{ p(1- p)}{n} }

=>      \sigma  =  \sqrt{\frac{ 0.52 (1- 0.52 )}{563} }

=>      \sigma  =   0.02106

Generally the  probability that the proportion of persons with a college degree will differ from the population proportion by less than 5% is mathematically represented as

            P(| \^ p -  p| < 0.05 ) =  P( - (0.05 - 0.52 ) <  \^ p <  (0.05 + 0.52 ))

  Here  \^ p is the sample proportion  of persons with a college degree.

So

 P( - (0.05 - 0.52 ) <  \^ p <  (0.05 + 0.52 )) = P(\frac{[[0.05 -0.52]]- 0.52}{0.02106} < \frac{[\^p - p] - p}{\sigma }  < \frac{[[0.05 -0.52]] + 0.52}{0.02106} )

Here  

    \frac{[\^p - p] - p}{\sigma }  = Z (The\ standardized \  value \  of\  (\^ p - p))

=> P( - (0.05 - 0.52 ) <  \^ p <  (0.05 + 0.52 )) = P[\frac{-0.47 - 0.52}{0.02106 }  <  Z  < \frac{-0.47 + 0.52}{0.02106 }]

=> P( - (0.05 - 0.52 ) <  \^ p <  (0.05 + 0.52 )) = P[ -2.37 <  Z  < 2.37 ]

=>  P( - (0.05 - 0.52 ) <  \^ p <  (0.05 + 0.52 )) = P(Z <  2.37 ) - P(Z < -2.37 )

From the z-table  the probability of  (Z <  2.37 ) and  (Z < -2.37 ) is

  P(Z <  2.37 ) = 0.9911

and

  P(Z <  - 2.37 ) = 0.0089

So

=>P( - (0.05 - 0.52 ) <  \^ p <  (0.05 + 0.52 )) =0.9911-0.0089

=>P( - (0.05 - 0.52 ) <  \^ p <  (0.05 + 0.52 )) = 0.9822

=> P(| \^ p -  p| < 0.05 ) = 0.9822

3 0
3 years ago
The amount spent on heating depends on the average temperature
anastassius [24]

That's D.


A(t) is the amount as a function of the temperature t.



7 0
3 years ago
Read 2 more answers
Need help solving these 3 equations, please help.
pantera1 [17]
1.) r=-1/3
2.) x=-33/29
3.) x=-4/5 x=2/5
3 0
3 years ago
Find the surface area of a square pyramid with base edge 5 m and slant height 10 m
Dominik [7]

h = 10 m

s = 10.3078 m

a = 5 m

e = 10.6066 m

r = 2.5 m

V = 83.3333 m^3

L = 103.078 m^2

B = 25 m^2

A = 128.078 m^2

3 0
3 years ago
Read 2 more answers
Robbie, has scored 120 so far this season. He has scored all of his points on 1-point extra point kicks and 3-point field goals.
joja [24]

Answer:

39 and 27

Step-by-step explanation:

GIVEN: Robbie, has scored 120 so far this season. He has scored all of his points on 1-point extra point kicks and 3-point field goals. He has made a total of 66 kicks.

TO FIND: How many of each kick has he made.

SOLUTION:

Lets extra point kicks made by Robbie be x

points scored using extra point kick =1

field goal kicks made by Robbie =66-x

point scored using field goal kick =3

Total points scored by Robbie =120

Total points scored are the sum of points scored by extra point kicks and field goal kicks.

1\times x+(66-x)3=120

198-2x=120

2x=78

x=39

total extra point kicks =39

total field goal kicks =66-39=27

Hence Robbie made 39 and 27 kicks of extra point kick and field goal kicks respectively.

6 0
3 years ago
Read 2 more answers
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