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julia-pushkina [17]
3 years ago
12

A random sample of 20 houses selected from a city showed that the mean size of these houses is 1880 square feet with a standard

deviation of 320 square feet. Assume that the sizes of all houses in this city have an approximate normal distribution. The upper bound the 90% confidence interval for the mean size of all houses in this city is: A. 2110 B. 1941 C. 1974 D. 1968 E. 1894
Mathematics
1 answer:
azamat3 years ago
3 0

Answer:

Option C

Step-by-step explanation:

Given that for a  random sample of 20 houses selected from a city showed that the mean size of these houses is 1880 square feet with a standard deviation of 320 square feet.

X, the sizes of houses is Normal

Hence sample mean will be normal with

Mean = 1880

and std dev = \frac{320}{\sqrt{20} } \\=71.5542

For 90% confidence interval critical value for t with degree of freedom 19 is

1.328

Confidence interval upper bound

= mean + margin of error

= 1880+1.328*71.55\\=1975

Option C is right

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Answer:

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Step-by-step explanation:

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33 x 22 = 726

Then find the area of the triangle. You can do this by first finding out the side lengths of the triangle:

33 - 24 = 9 and 22 - 12 = 10

Then multiply both sides and divide by two because it is a triangle:

10 x 9 = 90       90/2 = 45

Then subtract the area of the triangle from the rectangle:

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Step-by-step explanation:

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Mrrafil [7]
<h2>Hello!</h2>

The answer is:

The polynomial that can be simplified to a difference of squares is the second polynomial:

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<h2>Why?</h2>

To solve this problem, we need to look for which of the given quadratic terms given for the different polynomials can be a result of squaring (elevating by two).

So,

Discarding, we have:

The quadratic terms of the given polynomials are:

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We have that the coefficients of the quadratic terms that can be obtained by squaring are:

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