3 years ago

No one answer this I’ll mark you as 0

Mathematics

1 answer:

Dennis_Churaev [7]3 years ago

5 0

Answer:

bjdhadvd

Step-by-step explanation:

bhcxg vyogu fbgrdg zfyjvg hbv daihcgdj

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A watercolor painting is 24 inches long by 11 inches wide. Ramon makes a border around the watercolor painting by making a mat t

sergeinik [125]

Given: It is given that the length of the painting is 24 inches and the width is 11 inches.

To find: Area of the mat

Solution:

The watercolor painting is 24 inches long by 11 inches wide.

So, the area of the painting is:

$\text{Area of painting}=l\times b$

$\text{Area of painting}=24\times 11$

$\text{Area of painting}=264 \text{ in}^2$

The length of painting with mat is = 24 in + 3 in + 3 in = 30 in

The width of painting with mat = 11 in + 3 in + 3 in = 17 in

$\text{Area of painting with mat}=30\times 17$

$\text{Area of painting with mat}=510 \text{ in}^2$

Now to calculate the area of mat subtracts the area of painting from the area of the mat.

$\text{Area of mat}=\text{Area of painting with mat}-\text{Area of painting}\\$

$\text{Area of mat}=510-264$

$\text{Area of mat}=246 \text{ in}^2$

Hence, the area of the mat is 246 in².

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A triangle has lengths of 3 cm, 5 cm, and 9 cm, can it form 1 or more triangles?

AlladinOne [14]

Answer:Yes

Step-by-step explanation:

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ra1l [238]

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Suppose a squad patio has an area of 441 square feet. Use the formula for the area of a square to find the length of each side o

Sonja [21]

For a square: $A=s^{2}$

Solve for the length of a side by taking the square root of both sides:
$\sqrt{A}=\sqrt{s^{2}}$
$\sqrt{A}=s$

Now we can substitute known values:
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Your equation is gonna be
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