This is a quadratic equation, i.e. an equation involving a polynomial of degree 2. To solve them, you must rearrange them first, so that all terms are on the same side, so we get
i.e. now we're looking for the roots of the polynomial. To find them, we can use the following formula:
where is a compact way to indicate both solutions
and
, while
are the coefficients of the quadratic equation, i.e. we consider the polynomial
.
So, in your case, we have
Plug those values into the formula to get
So, the two solutions are
Select all the polygons that can be formed by the intersection of a plane and a cube. A. triangle B. square C. rectangle D. pent
1 answer:
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Answer:
z = 137°
Step-by-step explanation:
Hope this helps