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Using a geometric sequence, it is found that after 3 rounds, 8 teams are left.
In a geometric series, the quotient between consecutive terms is always the same, and it is called common ratio q.
The general equation of a geometric series is given by:

In which
is the first term.
In this problem:
- 64 teams were invited, thus
. - After each round, half the teams are eliminated, thus
.
The <u>number of teams after 3 rounds</u> is the 4th term of sequence, as the first is the initial number(0 rounds), thus:



After 3 rounds, 8 teams are left.
A similar problem is given at brainly.com/question/25317689
Answer:
6224
Step-by-step explanation:
Just multiply the two subjects.
Hope this helps :)
Answer:
Step-by-step explanation:
Let's "complete the square," which will give us the vertex of this vertical, opens-up parabola:
g(x) =x^2+4x+1 can be rewritten as g(x) =x^2+4x + 4 - 4 +1, where that +4 comes from squaring half of the coefficient of x.
Then we have g(x) =x^2+4x + 4 - 4 + 1 => g(x) = (x + 2)^2 - 3.
Comparing this to y = (x - h)^2 + k,
we see that the vertex, (h, k), is located at (-2, -3).
Plot this vertex. Also, plot the y-intercept (0, g(0) ), which is (0, 1).
This information is enough to permit graphing the function roughly.