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3 years ago

Factor this expression 10x²+ x -3

Mathematics

1 answer:

padilas [110]3 years ago

8 0

Answer:

x1= 1/2

x2=0,6

Step-by-step explanation:

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2 pounds of grapes cost $8 How do they cost per pound? How many pounds of grapes do you get per dollar?

stiks02 [169]

Answer:

$4 per pound and 0.25 pounds per dollar

Step-by-step explanation:

48 divided by 2 = $4

1 divided by 4 = 0.25

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3 years ago

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kykrilka [37]

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3 years ago

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Studentka2010 [4]

Answer:

(x + 3)(x + 8)

Step-by-step explanation:

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What are the first and last deciles of the standard Normal distribution?

aliya0001 [1]

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3 years ago

Find the radius of convergence, r, of the series. ∞ xn 2n − 1 n = 1 r = 1 find the interval, i, of convergence of the series. (e

Bingel [31]

Assuming the series is

$\displaystyle\sum_{n\ge1}\frac{x^n}{2n-1}$

The series will converge if

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{x^{n+1}}{2(n+1)-1}}{\frac{x^n}{2n-1}}\right|$

We have

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{x^{n+1}}{2(n+1)-1}}{\frac{x^n}{2n-1}}\right|=|x|\lim_{n\to\infty}\frac{\frac1{2n+1}}{\frac1{2n-1}}=|x|-\lim_{n\to\infty}\frac{2n-1}{2n+1}=|x|$

So the series will certainly converge if $-1$ , but we also need to check the endpoints of the interval.

If $x=1$ , then the series is a scaled harmonic series, which we know diverges.

On the other hand, if $x=-1$ , by the alternating series test we can show that the series converges, since

$\left|\dfrac{(-1)^n}{2n-1}\right|=\dfrac1{2n-1}\to0$

and is strictly decreasing.

So, the interval of convergence for the series is $-1\le x$ .

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3 years ago

Factor this expression 10x²+ x -3​

Factor this expression 10x²+ x -3