A 52-card deck is made up of an equal number of diamonds, hearts, spades, and clubs. Because there are 4 suits, there is a 1/4 chance to draw one of them, in our case, spades.
There are 4 aces in a 52-card deck, so the chance of drawing one is 4/52, or 1/13.
The question asks for the probability of drawing an ace or a spade. Because it uses the word "or," we add the probabilities together. This is because there is a chance of drawing either of the cards; it doesn't have to meet both requirements to satisfy the statement.
However, if the question were to say "and," we would multiply the two probabilities.
Let's add 1/4 and 1/13. First, we can find a common denominator. We can use 52 because both fractions can multiply into it (since the ratio came from a deck of 52 cards as well).


Now we can add them together.

This cannot be simplified further, so the probability is 17 in 52, or 33%.
hope this helps!
Answer:
37.59 nautical miles
Explanation:
Distance = Speed x Time
The speed of the first ship = 12 knots
Thus, the distance covered after 1.5 hours

The speed of the second ship = 22 knots
Thus, the distance covered after 1.5 hours

The diagram representing the ship's path is drawn and attached below:
The angle at port = 90 degrees.
The triangle is a right triangle.
Using Pythagorean Theorem:
![\begin{gathered} c^2=a^2+b^2 \\ c^2=18^2+33^2 \\ c^2=324+1089 \\ c^2=1413 \\ c=\sqrt[]{1413} \\ c=37.59\text{ miles} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20c%5E2%3Da%5E2%2Bb%5E2%20%5C%5C%20c%5E2%3D18%5E2%2B33%5E2%20%5C%5C%20c%5E2%3D324%2B1089%20%5C%5C%20c%5E2%3D1413%20%5C%5C%20c%3D%5Csqrt%5B%5D%7B1413%7D%20%5C%5C%20c%3D37.59%5Ctext%7B%20miles%7D%20%5Cend%7Bgathered%7D)
The two ships are 37.59 nautical miles apart after 1.5 hours.
b = number of tickets sold before
a = number of tickets sold after
cost of a ticket = number of tickets times cost per ticket
before cost = 39.95b
after cost = 54.95a
total cost = 925000
39.95b + 54.95a = 925000
total number tickets = 20000
b + a = 20000
we have
39.95b + 54.95a = 925000
b + a = 20000
multiply second equation by -39.95 and add to first equation
39.95b + 54.95a = 925000
-39.95b-39.95a = -799000 +
0b+15a = 126000
15a = 126000
divide bot sides by 15
a = 8400
sub back
b + a = 20000
b+8400 = 20000
minus 8400 both sides
b = 11600
11,600 tickets sold before
8400 tickets sold after
It would be 9, 9 1/2, 10, and 10 1/2. I think.
Answer:
2000
Step-by-step explanation:
(4x5) x 100