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chubhunter [2.5K]
3 years ago
7

Find the interquartile range of the data.

Mathematics
1 answer:
SCORPION-xisa [38]3 years ago
8 0
The correct answer is D.14.
The interquartile range is the difference between the Upper Quartile and the Lower Quartile of a data set.

By arranging the numbers in the stem and leaf plot from lowest to highest value, you get an even set of data (31,33,35,41,43,46,48,49,49,50). By dividing the set into two, you get a lower half of your data (31,33,35,41,43) and an upper half (46,48,49,49,50). The lower quartile is the median or the midpoint of the lower half of your data while upper quartile is for the upper half. The lower quartiles is 35 and upper quartile is 49. The difference between the two is 14.
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Use Cramer's Rule to solve the following system: –2x – 6y = –26 5x + 2y = 13
andriy [413]
\bf \begin{cases}
-2x-6y&=-26\\
\quad 5x+2y&=13
\end{cases}\stackrel{\textit{determinant of the coefficients}}{D=
\begin{bmatrix}
-2&-6\\5&2
\end{bmatrix}}\implies (-4)-(-30)
\\\\\\
D=-4+30\implies \boxed{D=26}\\\\
-------------------------------\\\\

\bf x=\cfrac{D_x}{D}\implies x=\cfrac{
\begin{bmatrix}
\boxed{-26}&-6\\\\ \boxed{13}&2
\end{bmatrix}}{D}\implies x=\cfrac{(-52)-(-78)}{26}
\\\\\\
x=\cfrac{-52+78}{26}\implies x=\cfrac{26}{26}\implies \boxed{x=1}\\\\
-------------------------------\\\\
y=\cfrac{D_y}{D}\implies y=\cfrac{
\begin{bmatrix}
-2&\boxed{-26}\\\\ 5&\boxed{13}
\end{bmatrix}}{D}\implies y=\cfrac{(-26)-(-130)}{26}
\\\\\\
y=\cfrac{-26+130}{26}\implies y=\cfrac{104}{26}\implies \boxed{y=4}
4 0
3 years ago
EASY!!!!
Zanzabum

Answer:

the answer is C LOLOLOL

5 0
3 years ago
Find all solutions in the interval [0, 2π) for 2 sin^2 x = sin x
Ede4ka [16]

Answer:

D

Step-by-step explanation:

2 sin²x=sin x

2 sin² x-sin x=0

sin x(2 sin x-1)=0

sin x=0

x=0,π

2 sin x-1=0

2 sin x=1

sin x=1/2= sin π/6,sin (π-π/6)

x=π/6,5π/6

4 0
3 years ago
If n = 6, then the value of n 2 is 12.<br> true or false
Vesna [10]
The answer is false. n^2 would become 6^2 which is equal to 36 not 12

8 0
3 years ago
Mike can ride his bike 15 miles per hour. How many miles could he reasonably ride in one day?
yuradex [85]

Answer:

360 miles

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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