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Orlov [11]
3 years ago
14

Can someone please help me on this one?

Mathematics
2 answers:
tensa zangetsu [6.8K]3 years ago
7 0
8 is the correct answer
joja [24]3 years ago
6 0
(4-2)/ (2^-3)
(4-2)=2
(2^-3)= 0.125

so
(2) / (0.125)
That is 16

Hope this helps :)
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Krutika and Natasha win some money and share it in the ratio 3:4. Krutika gets £39. How much did Natasha get?
grin007 [14]

Answer:

22.28 Pounds

Step-by-step explanation:

Add 3+4=7

39 ÷ 7=5.57

Because Natasha has the ratio of 4 she would get

5.57 × 4=22.28

Answer=22.28

4 0
2 years ago
What is 1(y), when y=-7/12?
Salsk061 [2.6K]

Answer: -7/12

Step-by-step explanation: an number multiplied by 1 is itself

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Jaden sells a painting for 10 times the original price he sells a painting for $45.50 what was the original price of this painti
Ymorist [56]
x-\ original\ price\\\\
10x=45,50\ \ \ \ | divide\ by\ 10\\\\
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6 0
3 years ago
Read 2 more answers
Which of the following expressions represents the distance between-1/4 and 3/4
Shalnov [3]

Answer:

|-1/4 - 3/4|

Step-by-step explanation:

To get the distance, take the absolute value of the second point minus the first point

| 3/4 - - 1/4|

|3/4 +  1/4|

We can also  take the absolute value of the first point minus the second point

|-1/4 - 3/4|

4 0
3 years ago
The Colonel spots a campfire at a bearing N 59∘59∘ E from his current position. Sarge, who is positioned 242 feet due east of th
Rashid [163]

Answer:

i. Colonel is about 201 feet away from the fire.

ii. Sarge is about 125 feet away from the fire.

Step-by-step explanation:

Let the Colonel's location be represented by A, the Sarge's by B and that of campfire by C.

The total angle at the campfire from both the Colonel and Sarge = 59^{0} + 34^{0}

                                           = 93^{0}

Thus,

<CAB = 90^{0} - 59^{0} = 31^{0}

<CBA = 90^{0} - 34^{0} = 56^{0}

Sine rule states;

\frac{a}{Sin A} = \frac{b}{Sin B} = \frac{c}{Sin C}

i. Colonel's distance from the campfire (b), can be determined by applying the sine rule;

\frac{b}{Sin B} = \frac{c}{Sin C}

\frac{b}{Sin 56^{0} } = \frac{242}{Sin 93^{0} }

\frac{b}{0.8290} = \frac{242}{0.9986}

cross multiply,

b = \frac{0.8290*242}{0.9986}

  = 200.8993

Colonel is about 201 feet away from the fire.

ii. Sarge's distance from the campfire (a), can be determined by applying the sine rule;

\frac{a}{Sin A} = \frac{c}{Sin C}

\frac{a}{Sin 31^{0} } = \frac{242}{Sin 93^{0} }

\frac{a}{0.5150} = \frac{242}{0.9986}

cross multiply,

a = \frac{0.5150*242}{0.9986}

  = 124.8073

Sarge is about 125 feet away from the fire.

8 0
3 years ago
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