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enyata [817]
3 years ago
10

Drea and Sajini both worked at a local ice cream shop over the summer. Together, they earned a total of $425. Drea earned $25 mo

re than Sajini. Write a system of two equations with two variables to model this problem. Use an algebraic method (substitution or linear combination) to solve the system. Graph both equations. Be sure to include the solution on your graph. How much did each person earn?
ps i can graph it myself i guess i just need the rest
Mathematics
2 answers:
Oksi-84 [34.3K]3 years ago
7 0

Answer:

Sajini = 200

Drea = 225

Step-by-step explanation:

d = amount Drea earned

s = amount Sajini earned

Together they earned 425

d+s =425

d = s+25


The system of equations

d+s =425

d = s+25


I will use substitution to solve

Substitute d= s+25 into the first equation

d+s =425

(s+25) + s = 425

Combine like terms

2s+25 =425

Subtract 25 from each side

2s+25-25 =425-25

2s = 400

Divide by 2

2s/2 =400/2

s =200

Sajini = 200

Now we need to find d

d = s+25

d = 200 + 25

d = 225

Drea = 225


Tema [17]3 years ago
6 0

Answer:

Drea: $225

Sajini: $200

Step-by-step explanation:

D + S = 425

D = S + 25

S + 25 + S = 425

2S = 400

S = 200

D = 200 + 25 = 225

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Answer:

(a) The value of P (X ≤ 2) is 0.8729.

(b) The value of P (X ≥ 5) is 0.0072.

(c) The value of P (1 ≤ X ≤ 4) is 0.7154.

(d) The probability that none of the 25 boards is defective is 0.2774.

(e) The expected value and standard deviation of <em>X</em> are 1.25 and 1.09 respectively.

Step-by-step explanation:

The random variable <em>X</em> is defined as the number of defective boards.

The probability that a circuit board is defective is, <em>p</em> = 0.05.

The sample of boards selected is of size, <em>n</em> = 25.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={25\choose x}0.05^{x}(1-0.05)^{25-x};\ x=0,1,2,3...

(a)

Compute the value of P (X ≤ 2) as follows:

P (X ≤ 2) = P (X = 0) + P (X = 1) + P (X = 2)

P(X\leq =x)=\sum\limits^{2}_{x=0}{{25\choose x}0.05^{x}(1-0.05)^{25-x}}\\=0.2774+0.3650+0.2305\\=0.8729

Thus, the value of P (X ≤ 2) is 0.8729.

(b)

Compute the value of P (X ≥ 5) as follows:

P (X ≥ 5) = 1 - P (X < 5)

              =1-\sum\limits^{4}_{x=0}{{25\choose x}0.05^{x}(1-0.05)^{25-x}}\\=1-0.9928\\=0.0072

Thus, the value of P (X ≥ 5) is 0.0072.

(c)

Compute the value of P (1 ≤ X ≤ 4) as follows:

P (1 ≤ X ≤ 4) = P (X = 1) + P (X = 2) + P (X = 3) + P (X = 4)

                   =\sum\limits^{4}_{x=1}{{25\choose x}0.05^{x}(1-0.05)^{25-x}}\\=0.3650+0.2305+0.0930+0.0269\\=0.7154

Thus, the value of P (1 ≤ X ≤ 4) is 0.7154.

(d)

Compute the value of P (X = 0) as follows:

P(X=0)={25\choose 0}0.05^{0}(1-0.05)^{25-0}=1\times 1\times 0.277389=0.2774

Thus, the probability that none of the 25 boards is defective is 0.2774.

(e)

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E(X)=np=25\times 0.05=1.25

Compute the standard deviation of <em>X</em> as follows:

SD(X)=\sqrt{np(1-p)}=\sqrt{25\times 0.05\times (1-0.05)}=1.09

Thus, the expected value and standard deviation of <em>X</em> are 1.25 and 1.09 respectively.

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