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yaroslaw [1]
3 years ago
11

I need help ASAP PLEASE please...

Mathematics
1 answer:
lys-0071 [83]3 years ago
3 0

Answer:λ= v X f

v= λ X f

f= λ X v

v= λ / f

Step-by-step explanation:

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The length of a rectangle is seven units more than it's width if the width is doubled and the length is increased by two the are
My name is Ann [436]

Answer:

length = 10 units; width = 3 units

Step-by-step explanation:

Let the width = w

Then the length is w + 7

Original area: w(w + 7)

Double the width: 2w

Increase the length by 2: w + 9

Area of new rectangle: 2w(w + 9)

Area of new rectangle = w(w + 7) + 42

2w(w + 9) = w(w + 7) + 42

2w^2 + 18w = w^2 + 7w + 42

w^2 + 11w - 42 = 0

(w + 14)(w - 3) = 0

w + 14 = 0 or w - 3 = 0

w = -14 or w = 3

A width cannot be negative, so we discard w = -14.

The original width is 3 units.

The length is 7 more than the width, so the length is 10 units.

7 0
3 years ago
Read 2 more answers
Data from the article "The Osteological Paradox: Problems inferring Prehistoric Health from Skeletal Samples" (Current Anthropol
iris [78.8K]

Answer:

(a) P (X < 109.78) = 0.9484.

(b) P (X < 109.78) = 0.9484.

(c) P (97 < X < 106) = 0.5328.

(d) P (X < 85.6 or X > 111.4) = 0.0369.

(e) P (X > 103) = 0.3085.

(f) P (X < 98.2) = 0.3821.

(g) P (100 < X < 124) = 0.5000.

(h) The middle 80% of all heights of 5 year old children fall between 92.31 and 107.70.

Step-by-step explanation:

It is provided that <em>X</em> follows a Normal distribution with mean, <em>μ</em> = 100 and standard deviation, <em>σ</em> = 6.

(a)

Compute the value of P (X > 89.2) as follows:

P (X>89.2)=P(\frac{X-\mu}{\sigma}>\frac{89.2-100}{6})\\=P(Z>-1.80)\\=P(Z

Thus, the value of P (X > 89.2) is 0.9641.

(b)

Compute the value of P (X < 109.78) as follows:

P (X

Thus, the value of P (X < 109.78) is 0.9484.

(c)

Compute the value of P (97 < X < 106) as follows;

P (97 < X < 106) = P (X < 106) - P (X < 97)

                          =P(\frac{X-\mu}{\sigma}

Thus, the value of P (97 < X < 106) is 0.5328.

(d)

Compute the value of P (X < 85.6 or X > 111.4) as follows;

P (X < 85.6 or X > 111.4) = P (X < 85.6) + P (X > 111.4)

                                       =P(\frac{X-\mu}{\sigma}\frac{111.4-100}{6})\\=P(Z1.9)\\=0.0082+0.0287\\=0.0369

Thus, the value of P (X < 85.6 or X > 111.4) is 0.0369.

(e)

Compute the value of P (X > 103) as follows:

P (X>103)=P(\frac{X-\mu}{\sigma}>\frac{103-100}{6})\\=P(Z>0.50)\\=14-P(Z

Thus, the value of P (X > 103) is 0.3085.

(f)

Compute the value of P (X < 98.2) as follows:

P (X

Thus, the value of P (X < 98.2) is 0.3821.

(g)

Compute the value of P (100 < X < 124) as follows;

P (100< X < 124) = P (X < 124) - P (X < 100)

                          =P(\frac{X-\mu}{\sigma}

Thus, the value of P (100 < X < 124) is 0.5000.

(h)

Compute the value of <em>x</em>₁ and <em>x</em>₂ as follows if P (<em>x</em>₁ < X < <em>x</em>₂) = 0.80 as follows:

P(X_{1}

The value of <em>z</em> is ± 1.282.

The value of <em>x</em>₁ and <em>x</em>₂ are:

-z=\frac{x_{1}-\mu}{\sigma} \\-1.282=\frac{x_{1}-100}{6}\\x_{1}=100-(6\times1.282)\\=92.308\\\approx92.31       z=\frac{x_{2}-\mu}{\sigma} \\1.282=\frac{x_{2}-100}{6}\\x_{2}=100+(6\times1.282)\\=107.692\\\approx107.70

Thus, the middle 80% of all heights of 5 year old children fall between 92.31 and 107.70.

5 0
3 years ago
I need help on now!!What is one difference??
Mumz [18]
They're alike because they each have 5 sides. They're different because figure A has no right angles but figure B does.

4 0
3 years ago
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Plss help due today !!!!
Sladkaya [172]

Answer:

$30

Step-by-step explanation:

She paid $24.72 for the 2 packages of chicken because $12.36×2=$24.72.

She paid $0.99 for the broccoli because $1.98×1/2=$0.99.

She paid $3.49 for the milk because one gallon of milk costs $3.49.

$24.72+$0.99+$3.49=$29.20.

$29.20+$0.80=$30.00.

She used $30.00 to pay for the items.

8 0
3 years ago
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How do you write 3,029,251 expand from
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3,000,000 + 20,000 + 9,000 + 200 + 50 + 1
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