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Lina20 [59]
3 years ago
12

Given tanø=(4/3) and 0<ø<(3pi/2) find cos20

Mathematics
1 answer:
ycow [4]3 years ago
5 0

Answer:

Step-by-step explanation:

hello :

here is an solution

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Help with inequality
Alona [7]

Answer:

1. x>20   2. x≤1     3.x<4     4.x>9      5.x≥-13

6 0
3 years ago
Find the surface area of the prism
Anastasy [175]

slated surface

17 × 20 = 340

2 triangle sides

2 × 8 × 15 ÷ 2 = 120

backside

8 × 20 = 160

bottom

15 × 20 = 300

sum all of it

340 + 120 + 160 + 300 = 920

can I get brainliest

4 0
3 years ago
If the expression (3^(d)*\sqrt(5))/(3^(2)*\sqrt(45)) is equal to 3, what is the value of d
Digiron [165]

3^d\cdot\dfrac{\sqrt5}{3^2\cdot\sqrt{45}}=3\\\\\dfrac{3^d\sqrt5}{3^2\sqrt{9\cdot5}}=3\qquad\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\\dfrac{3^d\sqrt5}{3^2\sqrt9\cdot\sqrt5}=3\\\\\dfrac{3^d}{3^2\cdot3}=3\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\\dfrac{3^d}{3^{2+1}}=3\\\\\dfrac{3^d}{3^3}=3\qquad\text{multiply both sides by}\ 3^3\\\\3^d=3\cdot3^3\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\3^d=3^{1+3}\\\\3^d=3^4\iff\boxed{d=4}

8 0
3 years ago
What is the answer 2(4y+1)=3y
SCORPION-xisa [38]
2(4y+1) = 3y. We need to solve for y.
First let's get ride of the parenthesis by developing 2(4y+1). This means to multiply 2 by 4y and 2 by 1, and add them.
2(4y+1) = 2*4y + 2*1 = 8y + 2
So 2(4y+1)=3y
8y+2 = 3y
Then you subtract 8y from each side to have the variables on a side and the numbers on the other:
3y - 8y = 8y + 2 - 8y
-5y = 2
Then you divide each side by -5 to get the variable y alone on a side and its value on the other:
(-5y)/-5 = 2/-5
y = -2/5

You can re-check your answer (very important):
2(4y + 1) = 2(4*-2/5 + 1) = -1.2
3y = 3 * -2/5 = -1.2
So 2(4y+1)=3y= -1.2
The answer has been approved.

Hope this Helps! :)
4 0
3 years ago
Identify the independent and dependent quantity in each situation. The cost of a long distance telephone call increases with the
blsea [12.9K]
Minutes is independent and the cost is dependent 

time is mostly always independent and cost is depending on the amount of time
8 0
3 years ago
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