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inessss [21]
3 years ago
8

A manufator makes two different sizes of spherical ball bEARINGS for use in motors. If the radius of the larger ball bearing is

twice the radius of the smaller one, then the volume of the larger ball bearing is how many times the volume of the smaller one? EXPLAIN!
A) 2
B) 4
C) 6
D) 8
Mathematics
2 answers:
Ede4ka [16]3 years ago
8 0

Answer:

D) 8

Step-by-step explanation:

V Large = 4/3 Pi (2r) Cube

V Small = 4/3 Pi (r) Cube

8 r Cube/ r Cube = 8

kotegsom [21]3 years ago
6 0

Answer:

Option D is the answer.

Step-by-step explanation:

Volume of sphere is given as:

\frac{4}{3}\pi r^{3}

Case 1:

Lets say the radius is 3 cm.

Volume = \frac{4}{3}\times3.14\times3\times3\times3

= 113.04 cubic cm

Case 2:

Lets say the radius is twice 3 cm that is 6 cm.

Volume = \frac{4}{3}\times3.14\times6\times6\times6

= 904.32 cubic cm.

The volume of the larger ball is \frac{904.32}{113.04} = 8 times the smaller one.

So, the answer is option D : 8 times.

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Doug hits a baseball straight towards a 15 ft high fence that is 400 ft from home plate. The ball is hit 2.5ft above the ground
Scorpion4ik [409]

Answer:

125.4\ \text{m/s}

Step-by-step explanation:

u = Initial velocity of baseball

\theta = Angle of hit = 30^{\circ}

x = Displacement in x direction = 400 ft

y = Displacement in y direction = 15 ft

y_0 = Height of hit = 2.5 ft

a_y = g = Acceleration due to gravity = 32.2\ \text{ft/s}^2

t = Time taken

Displacement in x direction

x=u_xt\\\Rightarrow x=u\cos\theta t\\\Rightarrow t=\dfrac{x}{u\cos\theta}\\\Rightarrow t=\dfrac{400}{u\cos30^{\circ}}\\\Rightarrow t=\dfrac{400}{u\dfrac{\sqrt{3}}{2}}\\\Rightarrow t=\dfrac{800}{u\sqrt{3}}

Displacement in y direction

y=y_0+u_yt+\dfrac{1}{2}a_yt^2\\\Rightarrow y=y_0+u\sin\theta t+\dfrac{1}{2}a_yt^2\\\Rightarrow 15=2.5+u\sin30^{\circ}(\dfrac{800}{u\sqrt{3}})+\dfrac{1}{2}\times -32.2\times (\dfrac{800}{u\sqrt{3}})^2\\\Rightarrow \dfrac{400}{\sqrt{3}}-\dfrac{10304000}{3u^2}-12.5=0\\\Rightarrow 218.44=\dfrac{10304000}{3u^2}\\\Rightarrow u=\sqrt{\dfrac{10304000}{3\times218.44}}\\\Rightarrow u=125.4\ \text{m/s}

The minimum initial velocity needed for the ball to clear the fence is 125.4\ \text{m/s}

5 0
3 years ago
What is the area??????
Westkost [7]
Your answer would be 91.1 units².
We can split this shape into a trapezium and a semicircle, and then find the area of both and add them.
To find the area of a trapezium, the formula is
(a + b)/2 × h, which means we do 14 (the length of AD) + 8 (the length of BC) = 22, and 22/2 = 11. Then we multiply 11 by the height of the trapezium, which is 6 because 10 - 4 = 6. This gives us the area of the trapezium as 66 units².
To find the area of a semicircle, the formula is πr²/2, and the radius is 4 because the diameter is 8 (16 - 8 = 8). This means we do π4²/2 = 16π\2 = 8π = 25.13.
Then we need to add together 66 and 25.13, which equals 91.13, or 91.1 to the nearest tenth.
I hope this helps!
7 0
4 years ago
Read 2 more answers
Compare. Write &lt;, &gt;, or=.<br>11. V8 +3( ) 8+ V3​
Levart [38]

Answer:

=

Step-by-step explanation:

v8 + 3 = 8 + v3

-3 -3

________________

v8 = 5 + v3

-v3 -v3

___________

v5 = 5

8 0
3 years ago
There are 35 boys in 6th grade. The number of girls in 6th grade is 40. Emma says that means the ratio of the number of boys in
garri49 [273]

Answer:

The correct ratio is 7:8, so no, Emma is not correct.

6 0
3 years ago
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If 9x + 10=y what is y??
lara31 [8.8K]

Answer:

above beat me to it he is right

4 0
3 years ago
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