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2 years ago

8

A manufator makes two different sizes of spherical ball bEARINGS for use in motors. If the radius of the larger ball bearing is

twice the radius of the smaller one, then the volume of the larger ball bearing is how many times the volume of the smaller one? EXPLAIN!
A) 2
B) 4
C) 6
D) 8

2 answers:

Ede4ka [16]2 years ago

8 0

Answer:

D) 8

Step-by-step explanation:

V Large = 4/3 Pi (2r) Cube

V Small = 4/3 Pi (r) Cube

8 r Cube/ r Cube = 8

kotegsom [21]2 years ago

6 0

Answer:

Option D is the answer.

Step-by-step explanation:

Volume of sphere is given as:

$\frac{4}{3}\pi r^{3}$

Case 1:

Lets say the radius is 3 cm.

Volume = $\frac{4}{3}\times3.14\times3\times3\times3$

= 113.04 cubic cm

Case 2:

Lets say the radius is twice 3 cm that is 6 cm.

Volume = $\frac{4}{3}\times3.14\times6\times6\times6$

= 904.32 cubic cm.

The volume of the larger ball is $\frac{904.32}{113.04}$ = 8 times the smaller one.

So, the answer is option D : 8 times.

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Liliana is making a vase with a circular base. She wants the area of the base to be between 135 cm2 and 155 cm2. Which circle co

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(b) Circle C is shown. Line segment A C is a radius with length 7 centimeters.

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$Minimum\ Area = 135cm^2$

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Required

Which circle could she use

To do this, we simply calculate the areas of all the given circles

The area of a circle is:

$Area = \pi r^2$

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$Area = 114.04cm^2$

$b.\ r = 7cm$

The area is calculated as thus:

$Area = \pi r^2$

$Area = 3.14 * (7cm)^2$

$Area = 3.14 * 49cm^2$

$Area = 153.86cm^2$

<em></em>

$c.\ r = 8cm$

The area is calculated as thus:

$Area = \pi r^2$

$Area = 3.14 * (8cm)^2$

$Area = 3.14 * 64cm^2$

$Area = 200.96cm^2$

$d.\ r = 9cm$

The area is calculated as thus:

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