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AnnyKZ [126]
3 years ago
14

A mule deer can run one over four of a mile in 25 seconds. At this rate, which expression can be used to determine how fast a mu

le deer runs in miles per hour? A. twenty-five seconds over one-fourth mile = 36 miles per hour B. one-fourth mile over twenty-five seconds = 36 miles per hour C. one-fourth mile over twenty-five seconds = 100 miles per hour D. twenty-five seconds over one-fourth mile = 100 miles per hour
Mathematics
1 answer:
kondor19780726 [428]3 years ago
3 0

the answer is D. twenty-five seconds over one-fourth mile = 100 miles per hour.


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The mean gpr averages of a random sample of 36 college seniors is calculated to be 2.6. the population standard deviation is 0.3
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4 years ago
In a recent Super Bowl, a TV network predicted that 50 % of the audience would express an interest in seeing one of its forthcom
coldgirl [10]

Answer:

z= -0.968

We can conclude that we fail to reject the null hypothesis, and we can said that at 5% of significance the proportion of people who says that  they would watch one of the television shows not differs from 0.5 or 50% .  

Step-by-step explanation:

1) Data given and notation n  

n=106 represent the random sample taken

X=48 represent the people who says that  they would watch one of the television shows.

\hat p=\frac{48}{106}=0.453 estimated proportion of people who says that  they would watch one of the television shows.

p_o=0.5 is the value that we want to test

\alpha represent the significance level  

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that 50% of people who says that  they would watch one of the television shows.:  

Null hypothesis:p=0.5  

Alternative hypothesis:p \neq 0.5  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.453 -0.5}{\sqrt{\frac{0.5(1-0.5)}{106}}}=-0.968  

4) Statistical decision  

P value method or p value approach . "This method consists on determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level is not provided, but we can assume \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(z  

So based on the p value obtained and using the significance level assumed \alpha=0.05 we have p_v>\alpha so we can conclude that we fail to reject the null hypothesis, and we can said that at 5% of significance the proportion of people who says that  they would watch one of the television shows not differs from 0.5 or 50% .  

6 0
3 years ago
30 - -5n + 16 + 3n =
MatroZZZ [7]

Answer:

8n + 46

Step-by-step explanation:

Combine like terms. First, simplify the signs. two negatives directly next to each other equals one positive:

- (-5n) = + 5n

30 + 5n + 16 + 3n = (30 + 16) + (5n + 3n)

(30 + 16) = 46

(5n + 3n) = 8n

8n + 46 is your answer.

7 0
3 years ago
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