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3 years ago

Solve the following system of equations using any method 10x+13y=11 3x+14y=-27

1 answer:

Klio2033 [76]3 years ago

4 0

10x + 13y = 11....multiply by 3
3x + 14y = -27....multiply by -10
------------------
30x + 39y = 33 (result of multiplying by 3)
-30x - 140y = 270 (result of multiplying by -10)
-------------------add
- 101y = 303
y = 303/-101
y = -3

10x + 13y = 11
10x + 13(-3) = 11
10x - 39 = 11
10x = 11 + 39
10x = 50
x = 50/10
x = 5

solution is : (5,-3)

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At Billy's school, 80 students come to school by bicycle or by car. Together, the vehicles they arrive to school in have 270 whe

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Answer:

x = number of bicycles = 35

y = number of cars = 55

Step-by-step explanation:

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6 0

3 years ago

Please help

ASHA 777 [7]

Answer:

(-6,4)

Step-by-step explanation:

The equations are:

$x^2+4y^2=100\\4y-x^2=-20$

Solving for x^2 of the 2nd equation and putting that in place of x^2 in the 2nd equation we have:

$4y-x^2=-20\\x^2=4y+20\\-------\\x^2+4y^2=100\\4y+20+4y^2=100$

Now we can solve for y:

$4y+20+4y^2=100\\4y^2+4y-80=0\\y^2+y-20=0\\(y+5)(y-4)=0\\y=4,-5$

So plugging in y = 4 into an equation and solving for x, we have:

$x^2=4y+20\\x=+-\sqrt{4y+20} \\x=+-\sqrt{4(4)+20} \\x=+-\sqrt{36} \\x=6,-6$

So y = 4 corresponds to x = 6 & x = -6

The pairs would be

(6,4) & (-6,4)

<u><em>we see that (-6,4) falls in the 2nd quadrant, thus this is the solution we are looking for.</em></u>

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