Not sure but I think
a) 4/6 which is 66.67%
b) 2/6 which is 33.33%
c) 4/6 which is 66.67%
i haven’t even finished high school so please don’t blame me if im wrong I do think that is the answer
This requires the Poisson distribution, where
area = 5-acres
and mean number of field mice = 12 (in 5-acres of field)
therefore
lambda=12 (mean, given)
and the probability of k mice in the 5-acre field is given by the Poisson distribution as
P(X=k)=lambda^k * e^(-lambda) / k! ..............(1)
To find the probability of having LESS than 7 field mice, we add the probabilities of 0 to 6, which is
P(X<7)=P(X=0)+P(X=1)+...+P(X=6)
evaluating with equation (1) for X=0 to 6, we get:
0 0.0000061 0.0000742 0.0004423 0.0017704 0.0053095 0.0127416 0.025481Total = 0.045822
Answer: The probability that fewer than 7 field mice are found in the 5-acre field is 0.0458.
Answer:
its 10...
Step-by-step explanation:
I think your ok. thats enough info
Answer:
36995.1474
Step-by-step explanation:
multiply the area value by 2.471
