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aliina [53]
3 years ago
11

Solve /x-5/=3 A. x=2, x=8 B. x=-8, x=8 C. x=-2, x=2 D. x=-8, x=-2

Mathematics
1 answer:
zhenek [66]3 years ago
5 0

Answer:

A) x=2, 8

Step-by-step explanation:

abs(x-5)=3

x-5=3, x-5=-3

x=3+5=8,

x=-3+5=2

You might be interested in
-5(a + 3) = -55<br> What is the value of a?
Kobotan [32]

Answer:

a=8

Step-by-step explanation:

-5(a+3)=-55

First you times the bracket by -5

-5a-15=-55

Then you add the 15 to -55 because since the 15 is a negative on the right it has to be the opposite to the left

-5a=-40

Then you divide both sides by negative 5

-5a .     = .      -40  

---------         ----------

- 5                    -5

a= 8

5 0
4 years ago
Write a real-world scenario for the equation 10x + 2 = 8x + 8. Solve the equation.
Allisa [31]

Answer:

3

Step-by-step explanation:

Frank wants to find a number that is multiplied by 10 is 2 less than 8 times the number plus 8.

Hope that helps :)

5 0
3 years ago
Read 2 more answers
PLEASE HELP!!!! <br> What is the range of the data set? <br> 68 88 113 156 113 210 145
Vladimir [108]
The range of this data set is 142.
4 0
3 years ago
Solve k^2 + 13k + 30 = 0
kogti [31]
K² + 13k + 30 = 0

This is a quadratic equation. Let's attempt solving it by factorization.

Coefficient of k² = 1, last term = 30

Multiply these two together 1*30 = 30

We think of two numbers that multiply to give 30 and add to give the middle term 13.

The two numbers are 3 and 10.

3*10 = 30,   3 + 10 = 13.

we replace the 13k with 3k + 10k

 k² + 13k + 30 = 0

k² + 3k + 10k + 30 = 0

k(k + 3) + 10(k + 3) = 0

(k + 3)(k + 10) = 0

(k + 3) = 0 or  (k + 10) = 0

k = 0 - 3  or  k = 0 - 10

k = -3, or -10

I hope this helps.
4 0
4 years ago
What term can you add to 5/6x-4 to make it equivalent to 1/2x-4?
patriot [66]

\frac{-1}{3}x can be added to \frac{5}{6}x-4 to make it equivalent to \frac{1}{2}x-4.

Step-by-step explanation:

Let,

y be the term that can be added to given fraction.

Therefore;

(\frac{5}{6}x-4)+y=\frac{1}{2}x-4

Subtracting \frac{5}{6}x-4 from both sides to find y

(\frac{5}{6}x-4)-(\frac{5}{6}x-4)+y=\frac{1}{2}x-4-(\frac{5}{6}x-4)\\\\\frac{5}{6}x-4-\frac{5}{6}x+4+y=\frac{1}{2}x+4-\frac{5}{6}x+4\\\\y=\frac{1}{2}x-\frac{5}{6}x\\\\y=\frac{3-5}{6}x\\\\y=\frac{-2}{6}x\\\\y=\frac{-1}{3}x

\frac{-1}{3}x can be added to \frac{5}{6}x-4 to make it equivalent to \frac{1}{2}x-4.

Keywords: fraction, subtraction

Learn more about fractions at:

  • brainly.com/question/7153188
  • brainly.com/question/7151553

#LearnwithBrainly

6 0
4 years ago
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