Answer: 18.7 mph
Step-by-step explanation:
We want a unit rate where 1 is in the denominator, so we divide top and bottom by 41.1
***If you found my answer helpful, please give me the brainliest. :) ***
For this case we have the following difference equation:

Applying separable variables we have:

Integrating both sides we have:

applying exponential to both sides:

For y (1) = 1 we have:

Thus, the particular solution is:

Whose domain is all real.
Answer: y = 0.2 * exp ((3/2) x ^ 2) Domain: all real numbers
Small, because 1 divided by 8 = 0.125, and 3 divided by 4 = .75 Hope this helps!
Answer:
not sure man... goodluck tho
Hi!
To compare this two sets of data, you need to use a t-student test:
You have the following data:
-Monday n1=16; <span>x̄1=59,4 mph; s1=3,7 mph
-Wednesday n2=20; </span>x̄2=56,3 mph; s2=4,4 mph
You need to calculate the statistical t, and compare it with the value from tables. If the value you obtained is bigger than the tabulated one, there is a statistically significant difference between the two samples.

To calculate the degrees of freedom you need to use the following equation:

≈34
The tabulated value at 0,05 level (using two-tails, as the distribution is normal) is 2,03. https://www.danielsoper.com/statcalc/calculator.aspx?id=10
So, as the calculated value is higher than the critical tabulated one,
we can conclude that the average speed for all vehicles was higher on Monday than on Wednesday.