3 years ago

What is the product of 1.3 and 7.02?

Mathematics

1 answer:

stellarik [79]3 years ago

3 0

Answer: 9.126

Step-by-step explanation:yw

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Simplify (1/2k) (4k) + 12 2k 2 + 12 14k 2 2k + 12 14k

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(1/2) (4k) + 12 = 2k + 12

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3 years ago

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Give a 98% confidence interval for one population mean, given asample of 28 data points with sample mean 30.0 and sample standar

klio [65]

We have a sample of 28 data points. The sample mean is 30.0 and the sample standard deviation is 2.40. The confidence level required is 98%. Then, we calculate α by:

$\begin{gathered} 1-\alpha=0.98 \\ \alpha=0.02 \end{gathered}$

The confidence interval for the population mean, given the sample mean μ and the sample standard deviation σ, can be calculated as:

$CI(\mu)=\lbrack x-Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}},x+Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}}\rbrack$

Where n is the sample size, and Z is the z-score for 1 - α/2. Using the known values:

$CI(\mu)=\lbrack30.0-Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}},30.0+Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}}\rbrack$

Where (from tables):

$Z_{0.99}=2.33$

Finally, the interval at 98% confidence level is:

$CI(\mu)=\lbrack28.94,31.06\rbrack$

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1 year ago

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The graph increases untill day 4(slope= positive) and then is stays constant(slope=0). Starting at day 8 the slope changes to be negative

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2 years ago

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2 years ago

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