I need help finding the length of the segment RS.

Mathematics

1 answer:

Zielflug [23.3K]3 years ago

3 0

Answer:

14.25

Step-by-step explanation:

5.7*5/2=14.24*2/5, and 5.7*5/2=14.25

You might be interested in

The random variable X, representing the number of accidents in a certain intersection in a week, has the following probability d

ollegr [7]

Answer: 0.70

Step-by-step explanation:

Given : The random variable X, representing the number of accidents in a certain intersection in a week, has the following probability distribution:

x 0 1 2 3 4 5

P(X = x) 0.20 0.30 0.20 0.15 0.10 0.05

Using the above probability distribution , the the probability that in a given week there will be at most 3 accidents is given by :_

$P(\leq3)=P(0)+P(1)+P(2)+P(3)\\\\=0.20+0.30+0.20=0.70$

Hence, the required probability = 0.70

7 0

3 years ago

The scores on a test for a sample of 42 statistics students are summarized in the following table. 9, 90, 18, 80, 15, 70. Find t

igomit [66]

<h3>Answer: 78.6</h3>

Work Shown:

$\begin{array}{|c|c|} \cline{1-2}\text{Number of People} & \text{Score}\\\cline{1-2}9 & 90\\\cline{1-2}18 & 80\\\cline{1-2}15 & 70\\\cline{1-2}\end{array}$

Multiply across the rows to form a third column. Example: 9*90 = 810 in the first row.

$\begin{array}{|c|c|c|} \cline{1-3}\text{Number of People} & \text{Score} & \text{Number*Score}\\\cline{1-3}9 & 90 & 810\\\cline{1-3}18 & 80 & 1440\\\cline{1-3}15 & 70 & 1050\\\cline{1-3}\end{array}$