Consider the statement: 4 − 3 + 5 = −6 + 8 + 4. This is a mathematically correct

Mathematics

1 answer:

Alla [95]4 years ago

3 0

4 - 3 + 5 = -6 + 8 + 4 (cancel equal terms)

-3 + 5 = -6 + 8 (calculate)

2 = 2 (check the equality if its equal its true)

Solution is true

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-2x^(3) +3=-1x^(3) -1x^(2) +1x+1

Natali5045456 [20]

-2x³ + 3 = -x³ - x² + x + 1

Add x³ to both sides, and subtract 3 from both sides.

-2x³ + x³ = -x² + x + 1 - 3

Add like terms.

-x³ = -x²+ x - 2

Move all of the (X's) to both sides, by adding x² to both sides, and subtracting x form both sides.

-x³ + x² - x = -2

~Hope I helped!~

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3 years ago

Rationalize the denominator of square root of negative 9 over open parentheses 4 minus 7 i close parentheses minus open parenthe

AlekseyPX

The answer is
$\frac{-6i-3}{5}$ .

Before we rationalize the denominator, we must simplify the numerator and denominator. We evaluate the square root on the top, and combine like terms on the bottom:
$\frac{\sqrt{-9}}{(4-7i)-(6-6i)}
\\
\\=\frac{\sqrt{9i^2}}{4-6-7i--6i}
\\
\\=\frac{3i}{-2-i}$

To rationalize the denominator, we multiply by the conjugate. The conjugate is found by making the imaginary term of the complex number, the i part, the opposite sign. The conjugate of -2-i is -2+i:

$\frac{3i}{-2-i}\times \frac{-2+i}{-2+i}
\\
\\=\frac{3i(-2+i)}{(-2-i)(-2+i)}
\\
\\=\frac{3i\times -2 + 3i\times i}{-2\times -2 + -2\times i + -2\times -i + -i\times i}
\\
\\=\frac{-6i+3i^2}{4-2i+2i-i^2}
\\
\\=\frac{-6i+3(-1)}{4-i^2}=\frac{-6i-3}{4-(-1)}=\frac{-6i-3}{5}$

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4 years ago