What number is 11/5 of 20?

Mathematics

1 answer:

Anna007 [38]3 years ago

3 0

Answer:

Step-by-step explanation:

11/5 of 20 is the same as 11/5 times 20. You can cancel out the fives to get 11 times 4 or 44

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Donna the trainer has two solo workout plans that she offers her clients: Plan A and Plan B. Each client does either one or the

kykrilka [37]

X=hours of plan A
y=hours of plan B

wed: 5x+6y=12
thu: 3x+2y=6

so
5x+6y=12 and
3x+2y=6
we can eliminate y's by multiplying 2nd equation by -3 and adding to first equation

-9x-6y=-18
5x+6y=12 +
-4x+0y=-6

-4x=-6
divid both sides by -4
x=-6/-4
x=3/2
x=1.5

sub back

3x+2y=6
3(1.5)+2y=6
4.5+2y=6
2y=1.5
y=0.75

Plan A=1.5 hours
Plan B=0.75 hours

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3 years ago

20 POINTS PLEAE HELP!!!!!!!!!!!!!!!

Alina [70]

His first payment is $100, thus a₁ = 100.

the next "term", month will be 1.1 times more than the one before, namely r = 1.1, the common ratio.

$\bf \qquad \qquad \textit{sum of a finite geometric sequence}
\\\\
S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
r=\textit{common ratio}\\
----------\\
a_1=100\\
r=1.1\\
n=20
\end{cases}$

$\bf \sum\limits_{i=1}^{20}~100(1.1)^{i-1}\qquad \qquad\qquad \qquad S_{20}=100\left( \cfrac{1-1.1^{20}}{1-1.1} \right)
\\\\\\
S_{20}=100\left( \cfrac{1-\stackrel{\approx}{6.727499949}}{-0.1} \right)\implies S_{20}\approx 100(57.27499949)
\\\\\\
S_{20}\approx 5727.4999493256$

is the serie divergent or convergent?

well, to make it short, when the common ratio is 0 < | r | < 1, namely a fraction between 0 and 1, only then the serie is convergent, namely it reaches a fixed value, now in this case, 1.1 is a value larger than anything between 0 and 1, so no dice.

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3 years ago

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Which function has an inverse function?

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Answer:

x=25.y2+755

y=x/25.2+755

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Use the graph to answer the question. About how many more website hits were there on Tuesday than on Monday? A. 700 B. 400 C. 60

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Two cars, car X and car Y , start moving from the same point P on a cross intersection. Car X is travelling east and car Y is tr

agasfer [191]

Let the distance traveled by car X be x km
let the distance traveled by car Y by y km 
their paths form a right-angled triangle. 
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D^2 = x^2 + y^2 
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dD/dt = (x dx/dt + y dy/dt)/D 

at the given case: 
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