120 = 15% x
15% = 0.15
x = 120 / 0.15 = 800
Answer: B. f(x)=(x+4)(x-2)^2(x+3)
Step-by-step explanation:
in the graph there's two negative x value and one positive x value
so the function should be in a form of f(x)= (x+a) (x-b)^2 (x+c)
the one with negative value has a square, (x-b)^{2}, because that's where the y = 0 (the point is hitting the (x,0))
Problem 3: Let x = price of bag of pretzels Let y = price of box of granola bars
We have Lesley's purchase: 4x+2y=13.50
And Landon's: 1x+5y=17.55
We can use the elimination method. Let's negate Landon's purchase by multiplying by -1. -1x-5y=-17.55
We add this four times to Lesley's purchase to eliminate the x variable.
2y-20y=13.50-70.2
-18y=-56.7
y = $3.15 = Price of box of granola bars
Plug back into Landon's purchase to solve for pretzels.
x+5*3.15=17.55
x+15.75=17.55
x = $1.80 = price of bag of pretzels
Problem 4.
Let w = number of wood bats sold
Let m = number of metal bats sold
From sales information we have: w + m = 23
24w+30m=606
Substitution works well here. Solve for w in the first equation, w = 23 - m, and plug this into the second.
24*(23-m)+30m=606
552-24m+30m=606
6m=54
m=9 = number of metal bats sold
Therefore since w = 23-m, w = 23-9 = 14. 14 wooden bats were sold.
$29.99=$30
$30-$15=$15
Ace's profit is $15
Since there are 8 students, each student gets 1/8 of the available cake. Since there is 3/4 of a cake available, they will get 1/8 of 3/4.
Source: https://www.wyzant.com/resources/answers/142015/there_are_8_students_in_a_group_and_3_4_cake_how_much_cake_will_each_student_get_if_divided_evenly
