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2 years ago

Find the area of the sector in terms of pi. 170 6 Area = [?] T

Mathematics

1 answer:

Harlamova29_29 [7]2 years ago

8 0

Answer:

see the attachment photo!

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I think I wrote question wrong, it’s what is the biggest even number I can make using all four numbers 4,6,3,1 I don’t think it’

Lera25 [3.4K]

Answer:

4 digits even number - 6314

8 0

3 years ago

7. for normal situations, the minimum speed limit throughout the u.s. interstate highway system is 72 km/hr which is 45 miles pe

gladu [14]

Answer:

Question 7: Distance = 237.6 km

Question 8: Distance = 399.3 km

Step-by-step explanation:

Question 7:

Given:

Minimum speed (s) = 72 km/hr

Time taken (t) = 3.3 hours.

We know that, distance traveled is equal to the product of speed and time.

Therefore using distance formula, we get:

Distance = Minimum speed × Time

Distance = $s\times t$

Distance = $72\times 3.3 = 237.6\ km$

Therefore, distance traveled at this speed is 237.6 km.

Question 8:

Maximum speed (S) = 121 km/hr

Time taken (T) = 3.3 hours.

We know that, distance traveled is equal to the product of speed and time.

Therefore using distance formula, we get:

Distance = Maximum speed × Time

Distance = $S\times T$

Distance = $121\times 3.3 = 399.3\ km$

Therefore, distance traveled at this speed is 399.3 km.

3 0

3 years ago

Use the expression shown below. 1 = (4 x 4 x 4 x 4 x 4) What is the value of the expression.

jeka57 [31]

Answer:

1024

Step-by-step explanation:

5 0

2 years ago

I need help pleaseee

krok68 [10]

Answer:

Step-by-step explanation:

5 0

3 years ago

With full explanation from the internet like before 3x2-6x+5=0

Elodia [21]

Answer:

$\sf x=1+i\sqrt{\dfrac{2}{3}} \ \quad and \quad \:x=1-i\sqrt{\dfrac{2}{3}}$

Explanation:

Given Expression:

3x² - 6x + 5 = 0

Use the Quadratic Formula:

$\sf x = \dfrac{ -b \pm \sqrt{b^2 - 4ac}}{2a} \ \ when \ \ ax^2 + bx + c = 0$

insert coefficients

$\Longrightarrow \sf x = \dfrac{-\left(-6\right)\pm \sqrt{\left(-6\right)^2-4\cdot \:3\cdot \:5}}{2\cdot \:3}$

$\Longrightarrow \sf x = \dfrac{\left6\right\pm \sqrt{-24} }{6}$

$\Longrightarrow \sf x = \dfrac{\left6\right\pm 2\sqrt{6}i}{6}$

$\Longrightarrow \sf x =1 \pm i\dfrac{\sqrt{6} }{3}$

$\Longrightarrow \sf x=1+i\sqrt{\dfrac{2}{3}}, \quad 1-i\sqrt{\dfrac{2}{3}}$

6 0

2 years ago

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