Answer:
Step-by-step explanation:
Given the following angle
We want to find angle AOB
∠AOC = 108°
∠AOB = 3x+4
∠BOC =8x−28
Check attachment for understanding
From the attachment, we notice that the sum of angle AOB and angle BOC equals to angle AOC.
∠AOB + ∠BOC = ∠AOC
3x + 4 + 8x —28 = 108
3x + 8x + 4—28 = 108
11x — 24 = 108
11x = 108 + 24
11x = 132
x = 132/11
x = 12°
∠AOB = 3(12) + 4
∠AOB = 36+4
∠AOB = 40°
Extra
∠BOC = 8x−28
∠BOC = 8(12)−28
∠BOC = 96−28
∠BOC = 68°
Its 60 on khan
:)
(y - yo) = m.(x - xo)
We have two points (-4, -1) and (1, 4)
(-1 - 4) = m.(-4 - 1)
(-5) = m.(-5)
m = (-5)/(-5)
m = 1
So the slope is 1
This is long ill write up a short summary of the answer in 2 mins