Given \qquad m \angle aoc = 108^\circm∠aoc=108 ∘ space, m, angle, a, o, c, equals, 108, degree \qquad m \angle aob = 3x + 4^
\circm∠aob=3x+4 ∘ space, m, angle, a, o, b, equals, 3, x, plus, 4, degree \qquad m \angle boc = 8x - 28^\circm∠boc=8x−28 ∘ space, m, angle, b, o, c, equals, 8, x, minus, 28, degree find m\angle aob∠aob, angle, a, o,
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2 answers:
Answer:
Step-by-step explanation:
Given the following angle
We want to find angle AOB
∠AOC = 108°
∠AOB = 3x+4
∠BOC =8x−28
Check attachment for understanding
From the attachment, we notice that the sum of angle AOB and angle BOC equals to angle AOC.
∠AOB + ∠BOC = ∠AOC
3x + 4 + 8x —28 = 108
3x + 8x + 4—28 = 108
11x — 24 = 108
11x = 108 + 24
11x = 132
x = 132/11
x = 12°
∠AOB = 3x+4
∠AOB = 3(12) + 4
∠AOB = 36+4
∠AOB = 40°
Extra
∠BOC = 8x−28
∠BOC = 8(12)−28
∠BOC = 96−28
∠BOC = 68°
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Answer:
Option B is correct.
The expression which is equivalent to is;
Explanation:
Given the equation: for all values of n.
The quadratic equation in this form;
First find two numbers that multiply to give ac and add to give b.
From the given equation;
a =1 , b = 26 and c =88
then,
the two number that multiply to give ac =88 is, 22 or 4
and they add up to give b=26 (i.e 22+4)
Now, rewrite the middle term i.e 26n with 22n and 4n , we have
Now, factor the first two terms and last two terms,
we see that is common to both terms so, we have;
Therefore, the expression is equivalent to
Check:
(n+4)(n+22) = =
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