Given \qquad m \angle aoc = 108^\circm∠aoc=108 ∘ space, m, angle, a, o, c, equals, 108, degree \qquad m \angle aob = 3x + 4^
\circm∠aob=3x+4 ∘ space, m, angle, a, o, b, equals, 3, x, plus, 4, degree \qquad m \angle boc = 8x - 28^\circm∠boc=8x−28 ∘ space, m, angle, b, o, c, equals, 8, x, minus, 28, degree find m\angle aob∠aob, angle, a, o,
b.ooaa ccbb
b.ooaa ccbb
2 answers:
Answer:
Step-by-step explanation:
Given the following angle
We want to find angle AOB
∠AOC = 108°
∠AOB = 3x+4
∠BOC =8x−28
Check attachment for understanding
From the attachment, we notice that the sum of angle AOB and angle BOC equals to angle AOC.
∠AOB + ∠BOC = ∠AOC
3x + 4 + 8x —28 = 108
3x + 8x + 4—28 = 108
11x — 24 = 108
11x = 108 + 24
11x = 132
x = 132/11
x = 12°
∠AOB = 3x+4
∠AOB = 3(12) + 4
∠AOB = 36+4
∠AOB = 40°
Extra
∠BOC = 8x−28
∠BOC = 8(12)−28
∠BOC = 96−28
∠BOC = 68°
You might be interested in
