3 years ago

Which value of b solves the equation? b^-3 = 1/216 A. –6 B. 6 C. 36 D. 72

Mathematics

2 answers:

viktelen [127]3 years ago

8 0

Answer:

Step-by-step explanation:

$\text{use}\\\\a^{-n}=\dfrac{1}{a^n}\\\\==========================\\\\b^{-3}=\dfrac{1}{216}\\\\\dfrac{1}{b^3}=\dfrac{1}{216}\qquad\text{inverse both sides}\\\\b^2=216\to b=\sqrt[3]{216}\\\\b=6\ \text{because}\ 6^3=216$

KatRina [158]3 years ago

4 0

The answer to the question

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