Y intercept is 24. ( y intercept is when x=0 )
<u>I'll assume you need to find the equation of the line that passes through those points.</u>
Answer:

Step-by-step explanation:
<u>Equation of a Line:</u>
The equation of a line passing through points (x1,y1) and (x2,y2) can be found as follows:

The given points are (-4,2) and (12,6), thus:

Operating:

Simplifying, the equation in point-slope form is:

I think it's C but I might not be right
Answer:
B)5/3
Step-by-step explanation:
"3x + 5y = 15."
Rewrite in slope-intercept form.
The slope-intercept form is
y=mx+b
where m is the slope and b is the y-intercept.
y=mx+b
Subtract 3x from both sides of the equation.
5y=15−3x
Divide each term by "5" and simplify.
5y/5=15/5−3x/5
"5" and "5" cancel each other out
Divide 15 by 5
y=3-3x/5
Reorder 3 and −3x/5
y=-3x/5+3
Rewrite in slope-intercept form.
y=−3/5x+3
Slope:-3/5
The equation of a perpendicular line to y=−3x/5+3 must have a slope that is the negative reciprocal of the original slope.
<em>m</em>perpendicular=−1/(−3/5)
Simplify the result.
mperpendicular=5/3
hope this helps!
18 is the answer hood this will help you