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Alona [7]
3 years ago
6

If the shape in the diagram rotates about the dashed line, which three-dimensional object will be formed?

Mathematics
3 answers:
SVETLANKA909090 [29]3 years ago
5 0

Answer:

Cone

Step-by-step explanation:

Rotation means the circular moment of an object about some axis or center.

In the given figure, the shape is rotated along the dashed line.

The size of the object remains same after rotation.

After rotating about the dashed line, we observe that the object formed is three- dimensional and is in the shape of a cone.

Elodia [21]3 years ago
3 0
It is a three-dimensional figure that remembers a cone, but the sides are not a right line but curved (concave) and the bottom is not plane but a convexed surface. This shape will wooble but not fall. I hope this explanation helps you because you didn't place the answer choices.
arnold3 years ago
0 0

a

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MrRa [10]
I think it’s the last one
4 0
3 years ago
Samantha is wrapping a present for her friend's birthday. The length of the box is 12 inches, width is 7 inches, and the height
loris [4]

Answer:

358 inches^2

Step-by-step explanation:

SA = 2(lw + lh + wh)

SA = 2 (12*7 + 12*5 + 7*5)

SA = 358

Hope this is helpful !!!!!

4 0
4 years ago
The question is attached
Bingel [31]

Answer:

We call the denominator rational.

Step-by-step explanation:

For example:

\frac{1}{\sqrt{2}} = \frac{\sqrt2}{\sqrt2 \cdot \sqrt2} = \frac{\sqrt2}{2}

It's clear that the denominator is now a rational number, not an irrational one anymore.

5 0
2 years ago
WHAT IS THE REMAINDER WHEN <img src="https://tex.z-dn.net/?f=32%5E%7B37%5E%7B32%7D%20%7D" id="TexFormula1" title="32^{37^{32} }"
Feliz [49]

Recall Euler's theorem: if \gcd(a,n) = 1, then

a^{\phi(n)} \equiv 1 \pmod n

where \phi is Euler's totient function.

We have \gcd(9,32) = 1 - in fact, \gcd(9,32^k)=1 for any k\in\Bbb N since 9=3^2 and 32=2^5 share no common divisors - as well as \phi(9) = 6.

Now,

37^{32} = (1 + 36)^{32} \\\\ ~~~~~~~~ = 1 + 36c_1 + 36^2c_2 + 36^3c_3+\cdots+36^{32}c_{32} \\\\ ~~~~~~~~ = 1 + 6 \left(6c_1 + 6^3c_2 + 6^5c_3 + \cdots + 6^{63}c_{32}\right) \\\\ \implies 32^{37^{32}} = 32^{1 + 6(\cdots)} =  32\cdot\left(32^{(\cdots)}\right)^6

where the c_i are positive integer coefficients from the binomial expansion. By Euler's theorem,

\left(32^{(\cdots)\right)^6 \equiv 1 \pmod9

so that

32^{37^{32}} \equiv 32\cdot1 \equiv \boxed{5} \pmod9

7 0
2 years ago
PLEASE HELP IM SO CONFUSED BY THIS
Yanka [14]
In a triangle, the three interior angles always add to 180°

m∠B = 180 - 30 - 80 = 70°

<span>D: 70</span>
4 0
4 years ago
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