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3 years ago

The charges for a delivery service are explained in the table what is the rate of change

Mathematics

1 answer:

alexandr1967 [171]3 years ago

4 0

I see no table so i can’t awnser it plz post one with it thanks

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Use the diagram to find the measurement of the given angle

Over [174]

Answer:

Step-by-step explanation:

FAC = FAE + EAD +CAD

We know FAC = 180 and CAD = 50 and EAD = 90

180 = FAE + 90 +50

Combine like terms

180 = FAE + 140

Subtract 140 from each side

180-140 = FAE +140-140

40 = FAE

6 0

3 years ago

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21. The volume of as sphere is 3,000pi m^3. What is the surface area of the sphere to the nearest square meter?

nevsk [136]

Pretty sure it's A ?? That's what I got. I'm taking this right now.

3 0

4 years ago

Ajar contains 16 beads. 4 beads are red, 4 are yellow, 5 are green, and 3 are blue.

steposvetlana [31]

Answer:

3/16

Total no.of beads = 16

No.of blue beads = 3

Probability of picking a blue bead = 3/16

Step-by-step explanation:

Hope this helps

can i get braineist pls

3 0

3 years ago

Find e^cos(2+3i) as a complex number expressed in Cartesian form.

ozzi

Answer:

The complex number $e^{\cos(2+31)} = \exp(\cos(2+3i))$ has Cartesian form

$\exp\left(\cosh 3\cos 2\right)\cos(\sinh 3\sin 2)-i\exp\left(\cosh 3\cos 2\right)\sin(\sinh 3\sin 2)$ .

Step-by-step explanation:

First, we need to recall the definition of $\cos z$ when $z$ is a complex number:

$\cos z = \cos(x+iy) = \frac{e^{iz}+e^{-iz}}{2}$ .

Then,

$\cos(2+3i) = \frac{e^{i(2+31)} + e^{-i(2+31)}}{2} = \frac{e^{2i-3}+e^{-2i+3}}{2}$ . (I)

Now, recall the definition of the complex exponential:

$e^{z}=e^{x+iy} = e^x(\cos y +i\sin y)$ .

So,

$e^{2i-3} = e^{-3}(\cos 2+i\sin 2)$

$e^{-2i+3} = e^{3}(\cos 2-i\sin 2)$ (we use that $\sin(-y)=-\sin y)$ .

Thus,

$e^{2i-3}+e^{-2i+3} = e^{-3}\cos 2+ie^{-3}\sin 2 + e^{3}\cos 2-ie^{3}\sin 2)$

Now we group conveniently in the above expression:

$e^{2i-3}+e^{-2i+3} = (e^{-3}+e^{3})\cos 2 + i(e^{-3}-e^{3})\sin 2$ .

Now, substituting this equality in (I) we get

$\cos(2+3i) = \frac{e^{-3}+e^{3}}{2}\cos 2 -i\frac{e^{3}-e^{-3}}{2}\sin 2 = \cosh 3\cos 2-i\sinh 3\sin 2$ .

Thus,

$\exp\left(\cos(2+3i)\right) = \exp\left(\cosh 3\cos 2-i\sinh 3\sin 2\right)$

$\exp\left(\cos(2+3i)\right) = \exp\left(\cosh 3\cos 2\right)\left[ \cos(\sinh 3\sin 2)-i\sin(\sinh 3\sin 2)\right]$ .

5 0

3 years ago

How many times do 2 goes into 19

ser-zykov [4K]

Nine and a half times.
***
you can put it fully nine times. You reach 18 like this. But you have 1 more to go until 19! So, just cut the 2 in half to get 1, and put that in!

8 0

3 years ago

Read 2 more answers