Brodt and Zimbardo found that shy women who were bombarded with loud noise and told that it would leave them with a pounding heart were subsequently no longer so shy when interacting with a handsome male.
a) with a pounding heart; no longer so shy
<u>Explanation:</u>
Shy is an emotion expressing nervousness, being reserved and timidity when communicating or being with some people. Shyness is generally observed in the person who has low self-confidence and inferiority complex.
Brodt and Zimbardo found that when a woman is continuously allowed to face loud noise, initially it may lead to pounding heart and subsequently they get used to it and they will be no longer shy. These scientists also found that when woman is interacting with the handsome male they will never feel shy.
Answer:
True
Explanation:
Let the allele for green color of pods be G
and the allele for yellow color of pods be g
Phenotype of true breeding parent with green colored seeds is GG
Phenotype of true breeding parent with yellow colored seeds is gg
In F1 cross
GG mates with gg
Genotype of offspring - Gg
Phenotype of offspring - Green seed
Since the offspring has both the allele for green and yellow seeds color but yet only green is expressed. This indicate that green allele dominated the expression of yellow allele thus, it can be concluded that green seed pods were dominant over yellow seed pods.
Answer:
P = f(TLTL) = 0,16
H = f(TLTS) = 0,48
Q = f(TSTS) = 0,36
Explanation:
Hello!
The allele proportion of any locus defines the genetic constitution of a population. Its sum is 1 and its values can vary between 0 (absent allele) and 1 (fixed allele).
The calculation of allelic frequencies of a population is made taking into account that homozygotes have two identical alleles and heterozygotes have two different alleles.
In this case, let's say:
f(TL) = p
f(TS) = q
p + q = 1
Considering the genotypes TLTL, TLTS, TSTS, and the allele frequencies:
TL= 0,4
TS= 0,6
Genotypic frequency is the relative proportion of genotypes in a population for the locus in question, that is, the number of times the genotype appears in a population.
P = f(TLTL)
H = f(TLTS)
Q = f(TSTS)
Also P + H + Q = 1
And using the equation for Hardy-Weinberg equilibrium, the genotypic frequencies of equilibrium are given by the development of the binomial:
So, if the population is in balance:
Replacing the given values of allele frecuencies in each equiation you can calculate the expected frequency of each genotype for the next generation as:
I hope you have a SUPER day!
In this question, there are no options given to choose from. So i would answer this question based on my knowledge. The most likely cause of the observed variation is adaptation and evolution. The birds of that island adapted to the food source and then they evolved as per the requirement of the place and food source.
Answer:
C
Explanation:
she is collecting data by counting the number of eggs that were laid
