Ask question

Ask question

All categories

4 years ago

9

A certain medicine is given in an amount proportion to a patient’s body weight. Suppose a patient weighing 132 pounds requires 1

43 milligrams of medicine. What is the amount of medicine required by a patient weighing 156 pounds?

2 answers:

Natali5045456 [20]4 years ago

7 0

Answer:

169 mg

Step-by-step explanation:

The ratio of medicine quantity to body weight is the same for both patients, so ...

amount/(156 lb) = (143 mg)/(132 lb)

Multiply by 156 lb:

amount = (143 mg)(156/132) = 169 mg

The patient requires 169 mg of medicine.

Veseljchak [2.6K]4 years ago

5 0

Answer:

160 milligrams......

You might be interested in

Combine the complex numbers

scoundrel [369]

Where is the insert image?

4 0

4 years ago

13 – 6x = 2(8 + 3x) <br> x= ???????

ruslelena [56]

Answer:

$13-6x=2\left(8+3x\right)$

$13-6x=16+6x$

$13-6x-13=16+6x-13$

$-6x=6x+3$

$-6x-6x=6x+3-6x$

$-12x=3$

$\frac{-12x}{-12}=\frac{3}{-12}$

$x=-\frac{1}{4}$

or

$x=-0.25$

8 0

3 years ago

Read 2 more answers

Is this adjacent or vertical

vazorg [7]

Is there supposed to be an image? Adjacent is adjoining, so like touching each other. Vertical is "up". Horizontal is "side"

4 0

3 years ago

Read 2 more answers

Solve the following rational equation for x.<br> x+5/9 = 11/15

zvonat [6]

I hope this helps x=0.17

6 0

3 years ago

Read 2 more answers

What’s the 5th term is 2,14,98

iragen [17]

$\bold{\huge{\orange{\underline{ Solution }}}}$

<h3><u>Correct </u><u>Question </u><u>:</u><u>-</u></h3>

What is the 5th term of an AP 2 , 14 ....98 .

<h3><u>Given </u><u>:</u><u>-</u><u> </u></h3>

<u>We </u><u>have </u><u> </u><u>AP</u><u>, </u>

$\sf{ 2 , 14 ,.... 98 }$
<u>AP </u><u>is </u><u>the </u><u>arithmetic </u><u>progression </u><u>or </u><u>a </u><u>sequence </u><u>of </u><u>numbers </u><u>in </u><u>which </u><u>succeeding </u><u>number </u><u>is </u><u>differ </u><u>from </u><u>preceeding </u><u>number </u><u>by </u><u>a </u><u>common </u><u>value</u><u>. </u>

<h3><u>Solution </u><u>:</u><u>-</u></h3>

<u>We </u><u>have </u><u>an </u><u>AP </u><u>:</u><u>-</u><u> </u><u>2</u><u> </u><u>,</u><u> </u><u>1</u><u>4</u><u> </u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>9</u><u>8</u>

<u>Therefore</u><u>, </u>

$\sf{a1\: or \:1st\: term = 2 }$
$\sf{a2 \:or \:2nd\: term = 14 }$
$\sf{an \:or\: last\: term = 98}$

<u>Here</u><u>, </u>

Common difference of an AP

$\sf{ a2 - a1 }$

$\sf{ = 14 - 2}$

$\sf{ = 12}$

Thus, The common difference is 12

<u>Now</u><u>, </u>

We know that,

$\sf{an = a1 + ( n - 1 )d}$

$\sf{a5 = 2 + ( 5 - 1 )12}$

$\sf{a5 = 2 + 4 × 12}$

$\sf{a5 = 2 + 48}$

$\sf{\red{a5 = 50}}$

Hence, The 5th term of given AP is 50

4 0

3 years ago