Answer:
look it up
Step-by-step explanation:
Answer:
y=2x^2 + 2x - 3 x -2 -1 0 1 2
Step By Step Explanation:
The values can be find by plugging the x values in the equation which gives us the y value ,
x -2 -1 0 1 2
y 1 -3 -3 1 9
(b) Plot the points on the graph and join by a smooth curve.
(c) The line y=1 will be passing through 1 and parallel to x-axis.
(d) solve 2x^2 + 2x - 3 = 1
Subtract 1 from both the sides ,
2x^2 + 2x - 2 = 0
Factoring out the 2 from the equation ,
2(x^2 + x - 1) = 0
x^2 + x - 1 = 0
Apply the quadratic formula
x=(-1-sqrt(5))/2 and x = (-1+sqrt(5))/5
The student messed up on step one. The proper factoring is (x-4) (x+2)
Standard equation of a circle: <em>(x-h)² + (y-k)² = r²</em> where <em>(h, k)</em> is the center and <em>r </em>is the radius. In the case of our equation here, <em>(x-5)² + (y+3)² = 25</em>, we can conclude that our circle has a center at (5, -3) and a radius of 5 units.
We can use the distance formula with the center (5, -3) and our point (2, 3) to see how far away they are...if the distance between them is less than the radius of the circle, it is on the interior. If it's equal, it's on the circle. If it's greater, it's on the exterior.
Distance =

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Distance =

Distance =

Distance =

The far right would be the correct answer.