Question

The length of a rectangle is 2cm less than twice the width. If y represents the width, state the inequality that the area of a rectangle is at least 15cm^2

Answer 1

The inequality that represents the area of the rectangle is: y(2y - 2) ≥ 15

What is the Area of a Rectangle?

• Area of Rectangle = length × width

Given:

width of rectangle = y cm

length of rectangle = (2y - 2) cm

Area = y(2y - 2)

We are given that the area of the rectangle is at least 15 sq cm.

Therefore, the inequality that represents the area of the rectangle is: y(2y - 2) ≥ 15

Learn more about area of rectangle on:

brainly.com/question/25292087

Answer 2

Answer:

Here, let width of the rectangle be x cm then length becomes xcm+5cm(length of the rectangle is 5cm longer than width)

Now, we know

Perimeter(p)=2(length+width)

40= 2(x+5+x)

40=2(2x+ 5)

40/2=2x+5

20=2x+5

20–5=2x

15/2=x

x=7.5

Now,

length=x+5=7.5+5=12.5cm

width=x=7.5cm

Therefore length is 12.5cm and width is 7.5cm